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EleoNora [17]
3 years ago
8

On a map of average annual temperature, why are the lower latitudes so much warmer than the higher latitudes?

Physics
2 answers:
Alenkasestr [34]3 years ago
3 0
Low altitudes are close to the equator. The temperatures are warmer as the latitude decreases, so they are very warm at low latitudes.

Readme [11.4K]3 years ago
3 0

Answer:

Explanation:

Weather is the combination of the parameters temperature, precipitation, wind, humidity, atmospheric pressure and cloudiness. These parameters are called weather elements. Climate factors are agents such as latitude, prevailing winds, sea currents, distance to the sea, altitude and relief, which modify, accentuate or limit the elements of the climate and give rise to different types of climates.

As mentioned, latitude is one of the factors that change the weather. Latitude is the angular distance from a point on the surface of the earth to the equator. It is measured in degrees, minutes and seconds.

The closer a place is to the equator, the solar energy will affect more vertically and with more intensity on it, so the warmer the temperatures will be. The further that point of the equator is found, the solar energy will reach it with a smaller angle. And if the point is near the poles, the sun's rays will arrive at a very small angle and only for a few months. This will make temperatures very low all year.

That is, in summary, the places that are at high altitudes (far from the equator) receive less sunlight than the places that are at low latitudes (near the equator) because the sun's rays have a greater or lesser obliqueness ( angle) over the earth's surface.

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1080000

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Answer:

<em>1.228 x </em>10^{-6}<em> mm </em>

<em></em>

Explanation:

diameter of aluminium bar D = 40 mm  

diameter of hole d = 30 mm

compressive Load F = 180 kN = 180 x 10^{3} N

modulus of elasticity E = 85 GN/m^2  = 85 x 10^{9} Pa

length of bar L = 600 mm

length of hole = 100 mm

true length of bar = 600 - 100 = 500 mm

area of the bar A = \frac{\pi D^{2} }{4} =  \frac{3.142* 40^{2} }{4} = 1256.8 mm^2

area of hole a = \frac{\pi(D^{2} - d^{2}) }{4} = \frac{3.142*(40^{2} - 30^{2})}{4} = 549.85 mm^2

Total contraction of the bar = \frac{F*L}{AE} + \frac{Fl}{aE}

total contraction = \frac{F}{E} * (\frac{L}{A} +\frac{l}{a})

==> \frac{180*10^{3}}{85*10^{9}} *( \frac{500}{1256.8} + \frac{100}{549.85}) = <em>1.228 x </em>10^{-6}<em> mm </em>

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