Orient the semi-circle arc such that it is symmetric with respect to the y-axis. Now, by symmetry, the electric field in the x-direction cancels to zero. So the only thing of interest is the electric field in the y-direction.
dEy=kp/r^2*sin(a) where k is coulombs constant p is the charge density r is the radius of the arc and a is the angular position of each point on the arc (ranging from 0 to pi. Integrating this renders 2kq/(pi*r^3). Where k is 9*10^9, q is 9.8 uC r is .093 m
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Answer:
The answer to your question is: Ke = 3000 Joules
Explanation:
Data
mass = 15 kg
speed = 20 m/s
Kinetic energy = ?
Equation


Ke = 3000 Joules
Answer:

Explanation:
f = Frequency = 75 Hz
B = Magnetic field = 
d = Diameter of cell = 
t = Time taken
= Angular frequency
The expression of emf is

Emf is maximum when
and N = number of turns = 1

The maximum emf that can be generated around the perimeter of a cell in this field is 
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