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3 years ago

Plzz help me please

Physics

1 answer:

olasank [31]3 years ago

6 0

Permanent magnet. An induced magnet would be created when a piece of iron (for example) is in contact with a magnet. Temporary magnets would be something like an electromagnet. Bar magnets are permanently magnetic unless we heat them or hammer them to cause their domains to loose alignment.

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What does it mean by "the mass of an object is 5 kg"

sergiy2304 [10]

Answer:

It has a mass of 5 kilograms

Explanation:

Kg is the unit of mass. So a 5kg object has a mass of 5kg. The weight you associate with it is only relevant on Earth (under its specific gravity)

credits: EliteDaMyth

4 0

3 years ago

Calculate the distance covered by a bus moving at a rate of 11.5km/h with a time of 2060seconds

vovangra [49]

Answer:

6.56km

Explanation:

Given parameters:

Speed = 11.5km/hr

Time = 2060s

Unknown:

Distance covered = ?

Solution:

Speed is distance divided by the time taken.

Speed = $\frac{distance}{time}$

Distance = Speed x time

Let us convert the seconds to hours;

3600s = 1hr

2060s = $\frac{2060}{3600}$ = 0.57hr

Now

Distance = 11.5km/hr x 0.57hr = 6.56km

5 0

3 years ago

Sterling Archer, despite failing repeatedly at pole-vaulting, is determined to master the skill. He is holding a vaulting pole p

LekaFEV [45]

Answer:

left hand: 133 N upward

right hand: 83N downward

Explanation:

10 cm = 0.1m

Let g = 10m/s2. The pole gravity force would be $F_p = 5*10 = 50 N$ . Suppose the pole mass distribution is uniform, this means the center of mass is at its geometric center, aka 5/2 = 2.5m from the top end.

In order for the system to stay balanced, the total net force and net moment must be 0

$F_L + F_R = F_p = 50 N$ where $F_L, F_R$ are the forces exerted by his left and right hand, respectively.

We will pick his right hand (0.1 m from the top end) as moment pivot point. The total moment generated by pole gravity and his left hand must be 0

Distance (or moment arm length) from pole center to his right hand is $R_p = 2.5 – 0.1 = 2.4 m$

Moment generated by gravity around his right hand is: $M_p = F_pR_p = 50*2.4 = 120 Nm$ counter-clockwise

Distance (or moment arm length) from left hand to his right hand is $R_L = 1 – 0.1 = 0.9 m$

Moment generated by force from his left hand around his right hand is: $M_L = F_LR_L = 1.9F_L Nm$ clockwise

Since the total moment must be 0, the clockwised-direction moment = counterclockwised-direction moment:

$0.9F_L = 120$

$F_L = 120 / 0.9 = 133 N$ upward

Therefore, the force exerted by his right hand must be 50 – 133 = -83 N or 83N downward

3 0

3 years ago

Plants are important to the balance of nature because they provide food and

Sphinxa [80]

Plants provide food and Carbon dioxide

5 0

3 years ago

Kim throws a beach ball up in the air. It reaches its maximum height 0.50s later. We can ignore air resistance. What was the bea

notka56 [123]

Answer:

The beach ball's velocity at the moment it was tossed into the air is <u>4.9 m/s.</u>

Explanation:

Given:

Time taken by the ball to reach maximum height is, $t=0.50\ s$

We know that, velocity of an object at the highest point is always zero. So, final velocity of the ball is, $v=0\ m/s$

Also, acceleration acting on the ball is always due to gravity. So, acceleration of the ball is, $a=g=-9.8\ m/s^2$

The negative sign is used as acceleration is a vector and it acts in the downward direction.

Now, we have the equation of motion relating initial velocity, final velocity, acceleration and time given as:

$v=u+at$

Where, 'u' is the initial velocity.

Plug in the given values and solve for 'u'. This gives,

$0=u-9.8(0.5)\\u=9.8\times 0.5\\u=4.9\ m/s$

Therefore, the beach ball's velocity at the moment it was tossed into the air is 4.9 m/s

3 0

3 years ago

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Plzz help me please ​

Plzz help me please