Answer:
about 19.6° and 73.2°
Explanation:
The equation for ballistic motion in Cartesian coordinates for some launch angle α can be written ...
y = -4.9(x/s·sec(α))² +x·tan(α)
where s is the launch speed in meters per second.
We want y=2.44 for x=50, so this resolves to a quadratic equation in tan(α):
-13.6111·tan(α)² +50·tan(α) -16.0511 = 0
This has solutions ...
tan(α) = 0.355408 or 3.31806
The corresponding angles are ...
α = 19.5656° or 73.2282°
The elevation angle must lie between 19.6° and 73.2° for the ball to score a goal.
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I find it convenient to use a graphing calculator to find solutions for problems of this sort. In the attachment, we have used x as the angle in degrees, and written the function so that x-intercepts are the solutions.
Hello! I do not understand this question very well but this is the best answer i got...I am very sorry if you do not like this you may report me if you like.
Inertia: One reason why its hard to get up in the morning for school.
Answer:
a) ω = 91.1 rad/s
b) KEr = 15.0 J
Explanation:
I = (2/3)mR²
ω = v/R
PE = KE
mgh = ½mv² + ½Iω²
mgh = ½mv² + ½(2/3)mR²(v/R)²
2gh = v² + (2/3)v²
2gh = 5/3v²
v² = 6gh/5
ω² = v²/R² = 6gh/5R²
a. At what rate was it rotating at the base of the hill?
ω = √(6(9.81)(9.00) / (5(0.226/2)²) = 91.1 rad/s
b. How much rotational kinetic energy did it then have?
KE = ½Iω² = ½(⅔)(0.426)(0.113)²(91.1²) = 15.044616
Given Information:
Resistance = R = 1.9 k
Ω
Capacitance = C = 30 uF
Initial charge = 30 uC
Final charge = 5 uC
Required Information:
Time taken to reduce the capacitor's charge to 5.0 μC = ?
Answer:
t = 0.101 seconds
Explanation:
The voltage across the capacitor is given by
V = V₀e^(–t/τ)
Where τ is time constant, V₀ is the initial voltage, V is the voltage after some time t
τ = RC
τ = 1900*30x10⁻⁶
τ = 0.057 sec
The initial voltage across the capacitor was
V₀ = Q/C
V₀ = 30/30
V₀ = 1 V
Voltage to reduce the charge to 5 uF
V = 5/30
V = 0.167 V
V = V₀e^(–t/τ)
0.167 = 1*e^(–t/0.057)
take ln on both sides
ln(0.167) = ln(e^(–t/0.057))
-1.789 = -t/0.057
t = 1.789*0.057
t = 0.101 seconds
On the equator, the sun rays directly fall and makes the places more heated.
As, we go up the equator, the sun rays fall horizontally and not directly.So, we experience temp. decrease