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Nadya [2.5K]
2 years ago
15

you throw a ball toward a wall at a speed 25.0 m/s and at an angle 40° above the horizontal. the wall is distance d = 22.0 m fro

m​
Physics
1 answer:
devlian [24]2 years ago
5 0

4.80m/s

(d) Since v y >0 when the ball hits the wall, it has not reached the highest point yet.

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Halogen is most likely to react to what
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Halogens therefore react most vigorously with Group 1 and Group 2 metals of all main group elements.
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What is the definition of energy ​
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Energy (in Physics) is the ability to do work.

5 0
3 years ago
The total resistance of a parallel circuit is 25 ohms. If the total current is 100mA, how much current is through a 220 ohm resi
gulaghasi [49]

Answer:

The current across the resistance is 0.011 A.

Explanation:

Total resistance, R = 25 ohms

Total current, I = 100 mA = 0.1 A

Let the voltage is V.

By the Ohm's law

V = I R

V = 0.1 x 25 = 2.5 V

Now the resistance is R' = 220 ohm

As they are in parallel so the voltage is same. Let the current is I'.

V = I' x R'

2.5 = I' x 220

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7 0
2 years ago
Which is an example of electrical energy being converted or changed into light energy?
Lera25 [3.4K]
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I just KNOW that there's a list of choices printed right there
next to he part that you copied, and for some mysterious
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Any flashlight, light bulb, laser, or spark ... like lightning ...
converts some electrical energy into some light energy.

8 0
3 years ago
Read 2 more answers
A test charge of -1.4 x 10-7 coulombs experiences a force of 5.4 x 10-1 newtons. Calculate the magnitude of the electric field c
VARVARA [1.3K]

Answer:

3.86×10⁶ Newton/coulombs

Explaination:

Applying,

E = F/q....................... Equation 1

Where E = Electric Field, F  = Force, q = charge.

From the question,

Given: F = 5.4×10⁻¹ N, q = -1.4×10⁻⁷ coulombs

Substitute these values into equation 1

E = 5.4×10⁻¹/ -1.4×10⁻⁷

E = -3.86×10⁶ Newtons/coulombs

Hence the magnitude of the electric field created by the

negative test charge is 3.86×10⁶ Newton/coulombs

5 0
2 years ago
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