Forms a thin layer of gases around earth

A soccer player kicks a ball from the ground with a speed of 16 m/s at an angle of 63°.

stepladder [879]

A. Horizontal component: 7.3 m/s

Explanation:

The horizontal component of the velocity is given by:

$v_x = v_0 cos \theta$

where

$v_0 = 16 m/s$ is the magnitude of the initial velocity

$\theta=63^{\circ}$ is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

$v_x = (16 m/s) cos 63^{\circ}=7.3 m/s$

B. Vertical component: 14.3 m/s

Explanation:

The vertical component of the velocity is given by:

$v_y = v_0 sin \theta$

where

$v_0 = 16 m/s$ is the magnitude of the initial velocity

$\theta=63^{\circ}$ is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

$v_y = (16 m/s) sin 63^{\circ}=14.3 m/s$

6 0

3 years ago

Systems in the body interact to carry out life functions. The muscles of the body are part of the musculoskeletal system. Which

SpyIntel [72]

Answer:

The answer is below!!

Explanation:

The skeletal system is made up of bones, ligaments and tendons. It shapes the body and protects organs. The skeletal system works with the muscular system to help the body move.

Hope I Helped!!

:)

4 0

2 years ago

Read 2 more answers

calculate the magnitude of the electric field intensity in vacuum at a distance of 20 cm from a charge of 5 * 10 raise to power

forsale [732]

Answer:

1.1259*10^9 Newton per Columb

Explanation:

the magnitude of the electric field intensity can be calculated using the expresion below;

E=Kq/r^2

Where k= constant

q= electric charge

r=distance= 2cm= 20*10^-2m( we convert to m for unit consistency

:,K=59*10^9 Columb

If we substitute the value into above formula we have

E=(9*10^9)*(5*10^-3)/(20*10^-2)^2

=1.1259*10^9 Newton per Columb

Therefore,the magnitude of the electric field intensity in vacuum at a distance of 20 cm is 1.1259*10^9 Newton per Columb

3 0

3 years ago

What does the term electron orbital describe? What does the term electron orbital describe? An electron orbital describes a thre

Yuliya22 [10]

Answer:

An electron orbital describes a three-dimensional space where an electron can be found 90% of the time.

Explanation:

According to Heisenberg's theory we cannot observe the position and velocity of an electron in an orbit, but if they were around the nucleus (in orbit), it would be possible to know its velocity and position, which would be contrary to the principle of Heisenberg So we can say that no electron revolves around a certain orbit around the nucleus, so we can only predict if the electron will be in the right position at the right time.

From there we find two definitions for electron orbital let's see:

Orbital is considered the region of space, where each electron spends most of its time.

Orbital is considered the region of space that is most likely to find an electron.

3 0

3 years ago

Two tiny conducting spheres are identical and carry charges of -20μC and +50μC. They are separeted by a distance of 2.50cm. (a)

Dahasolnce [82]

Answer:

$14400\ \text{N}$ , Attractive

$3240\ \text{N}$ , Repulsive

Explanation:

$q_1$ = -20 μC

$q_2$ = 50 μC

r = Distance between the charges = 2.5 cm

k = Coulomb constant = $9\times 10^9\ \text{Nm}^2/\text{C}^2$

Electrical force is given by

$F=\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=\dfrac{9\times 10^9\times (-20\times 10^{-6})\times (50\times 10^{-6})}{(2.5\times10^{-2})^2}\\\Rightarrow F=-14400\ \text{N}$

The magnitude of force each sphere will experience is $14400\ \text{N}$

Since the charges have opposite charges they will attract each other.

Now the charges are brought into contact with each other so the resultant charge will be

$q=\dfrac{q_1+q_2}{2}\\\Rightarrow q=\dfrac{-20+50}{2}\\\Rightarrow q=15\ \mu\text{C}$

$F=\dfrac{kq^2}{r^2}\\\Rightarrow F=\dfrac{9\times 10^9\times (15\times 10^{-6})^2}{(2.5\times 10^{-2})^2}\\\Rightarrow F=3240\ \text{N}$

The magntude of the force the spheres experience will be $3240\ \text{N}$

The spheres have the same charge now so they will repel each other.

7 0

3 years ago