Forms a thin layer of gases around earth

A visible disturbance propagates around a crowded soccer stadium when fans, section by section, jump up and then sit back down.

PolarNik [594]

Answer: Transverse wave

Explanation:

This type of wave is transverse wave. Transverse wave is a wave that occurs when the vibration of the medium is perpendicular to the direction of the wave. According to the question, the crowd were standing vertically but they were arranged in the stadium in the horizontal manner.

5 0

4 years ago

6th grade science If you answer this your the brainiest

motikmotik

Answer:

8. sketches and models helped the astronauts in their training program as they prepare for their missions

9. before building the Mars lander , students need to sketch their design

5 0

3 years ago

The left side of the heart creates a pressure of 120 mm Hg by exerting a force directly on the blood over an effective area of 1

jeka57 [31]

Answer:

23.99N

Explanation:

Given:

Pressure created by the heart = 120mm of hg

converting the pressure into the standard unit of N/m²

1mm of hg = $\frac{1}{760}atm=\frac{1}{760}\times 1.013\times10^5N/m^2$

now, 120 mm of hg in N/m² will be

120mm of hg = $\frac{12}{760}\times 1.013\times10^5N/m^2$

also

given effective area = 15.0 cm² = 15 × 10⁻⁴m²

Now,

Force = Pressure × Area

thus,

Force exerted will be = $\frac{120}{760}\times 1.013\times10^5N/m^2$ × 15 × 10⁻⁴m²

or

Force exerted will be = 23.99N

4 0

3 years ago

Read 2 more answers

A circular hole in an aluminum plate is 2.739 cm in diameter at 0.000°C. What is the change in its diameter when the temperature

prisoha [69]

Answer:

$L = 2.746 cm$

Explanation:

As we know that thermal expansion coefficient of aluminium is given as

$\alpha = 24 \times 10^{-6} per ^oC$

now we also know that after thermal expansion the final length is given as

$L = L_o(1 + \alpha \Delta T)$

here we know that

$L_o = 2.739 cm$

$\alpha = 24 \times 10^{-6}$

$\Delta T = 108 - 0= 108^oC$

now we will have

$L = 2.739(1 + 24 \times 10^{-6} (108))$

$L = 2.746 cm$

3 0

4 years ago

A lead ball is dropped 30 feet from a church tower. If the acceleration due to gravity is 9.8m s^-2, how long does it take the b

Alika [10]

final velocity of a falling object = 0

and acceleration of a falling object is negative

now using the expression ( Newton's 3rd equation of motion)

${v}^{2} = {u}^{2} - 2gs$

where the parameters have their usual meaning

making

${u}^{2} \: the \: subject$

thus

${u}^{2} = 2gs$

$u = \sqrt{2gs}$

from the question,

g= 9.8m/s^2

s = 30m

substitute them into the equation

$u = \sqrt{2(9.8 \times 30)}$

$u = \sqrt{588}$

u = 24.25m/s

but the question is demanding for time but not the initial velocity

so substitute them in the

Newton's first equation of motion

where

V = u - gt

but from the question,

v= 0 and the acceleration is negative because it's a free fall

substitute the values into the equation

0 = 24.24 -9.8t

making t the subject

9.8t = 22.24

dividing through by 9.8

9.8t/9.8 = 22.24/9.8

t = 2.3s . therefore, it would take 2.3s for the ball to hit the ground.

4 0

4 years ago