Answer:
11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.
Explanation:
Chloroacetic acid is an monoprotic acid.
Neutralization reaction: 
So, 1 mol of chloroacetic acid is neutralized by 1 mol of NaOH.
Molar mass of chloroacetic acid = 94.5 g/mol
So, 0.154 g of chloroacetic acid = 
moles of chloroacetic acid
= 0.00163 moles of chloroacetic acid
Lets assume V mL of 0.1400 M of NaOH is required to reach equivalence point.
So, number of moles of NaOH needed to reach equivalence point
= 
moles
So, 
or, V = 11.6
Hence, 11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.
Answer:
c
Explanation:
all fins are for movement
Answer:
Weaker attraction between its molecules than the green substance. It's molecules now move away from each other.
Explanation:
Liquid to gas.
Answer:
145 grams of a 0.480 % KCN solution contains 697 mg of KCN.
Explanation:
w/w % : The percentage mass or fraction is mass of the of solute present in 100 grams of the solution.
given = w/w% = 0.480 %
Mass of solute that KCN = 697 mg = 0.697 g
(1 mg = 0.001 g)
Mass of the solution = ? = x
x = 145.21 g ≈ 145 g
145 grams of a 0.480 % KCN solution contains 697 mg of KCN.
The ratio of atoms of potassium to ratio of atoms of oxygen is 2:1
