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Akimi4 [234]
3 years ago
14

If the load parameters are: Vln=600kV, Il=100A (resistive), calculate the source voltage and current when the line is 50Miles (s

hort), 150 Miles(medium), and 300 Miles (long).
Engineering
1 answer:
Archy [21]3 years ago
4 0

s 0Miles (short), 150 Miles(medium), and 300 Miles (long).

Explanation:

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For a turbulent flow of a fluid in 0.6 m diameter pipe, the velocity 0.15 m from the wall is 2.7 m/s. Estimate the wall shear st
MAVERICK [17]

Answer:

If the turbulent velocity profile in a pipe of diameter 0.6 m may be approximated by u/U=(y/R)^(1/7), where u is in m/s and y is in m and 0.15 m from the pipe.

Explanation:

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2 years ago
What does a peak flow meter allow you to assess?
Alex Ar [27]

Answer:

  peak flow and any engineering considerations related thereto

Explanation:

It should be no surprise that a peak flow meter will report peak flow, sometimes with important maximum-value, time-constant, or bandwidth limitations. There are many engineering issues related to flow rates. A peak flow meter can allow you to assess those issues with respect to the flows actually encountered.

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3 years ago
As a means of preventing ice formation on the wings of a small, private aircraft, it is proposed that electric resistance heatin
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Average heat flux=3729.82 W/m^{2}

Explanation:

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2 years ago
An error was reported in a software program by a user. Before that error can be diagnosed and fixed
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Answer:

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6 0
3 years ago
Read 2 more answers
Use Excel, MatLab or a similar program to plot carrier thermal velocity as a function of temperature for both electrons and hole
Sidana [21]

Answer:

Solution 2:

The thermal energy of any particle is given as = \frac{1}{2}mv^{2}

where m= Effective mass of the particle,

v= Velocity of the particle

The average kinetic energy is given as =  \frac{3}{2}KT,

where K= Boltzmann Constant

T= Temperautre of the particle

At equilibrium,

1/2 mv² =  3/2 KT

Hence, v= \sqrt{\frac{3KT}{m}}

As, effective mass ratio is calculated with respect to rest mass of electron,

melectron = 0.11 * 9.11 *10-31 kg

mhole =  0.35 *9.11 *10-31 kg

K = 1.38 × 10-23 m2 kg s-2 K-1

Plotting, over a range of temperature of 0 K to 400 K, we obtain the attached Graphs (attached).

Solution 3:

The above two curves plotted are not identical as seen. From the same value of Temperature, and under identical conditons, the Thermal velocity solely depends on effective mass ratio. And it is inversely proportional to effective mass ratio. More the effective mass ratio, less the thermal velocity and flatter the slope of the curve and vice versa. As, the mass ratio of holes is more than that of electrons, the curve of electrons has a steeper slope than that of holes. Hence, the curves are not just identical.

8 0
3 years ago
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