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jek_recluse [69]
3 years ago
13

Light from a helium-neon laser (λ = 633 nm) illuminates two slits spaced 0.50 mm apart. A viewing screen is 2.5 m behind the sli

ts. What is the spacing between two adjacent bright fringes?
Engineering
1 answer:
serg [7]3 years ago
7 0

Answer:

Explanation:

Given

wavelength \lambda =633\ nm

distance between two slits d=0.5\ mm

Screen is placed at a distance L=2.5\ m

Location of a (n+1)th bright fringe is given by

x_{n+1}=\frac{L}{2d}(n+1)\lambda

for nth bright fringe

x_n=\frac{L}{2d}(n)\lambda

Distance between two bright fringes

x_{n+1}-x_n=\frac{L}{2d}\cdot \lambda

x_{n+1}-x_n=\frac{2.5}{2\times 0.5\times 10^{-3}}\cdot 633\times 10^{-3}

x_{n+1}-x_n=1.582\ mm

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A 0.5 m^3 container is filled with a mixture of 10% by volume ethanol and 90% by volume water at 25 °C. Find the weight of the l
svp [43]

Answer:

total weight of liquid = 4788.25 N or 488.09 kg

Explanation:

given data

total volume = 0.5 m³

volume of ethanol = 10 %  of volume = 0.10 × 0.5 = 0.05 m³

volume of water = 90 % at 25 °C of volume = 0.90 × 0.5 = 0.45 m³

to find out

weight of the liquid

solution

we know that density of water at 25  is 997 kg/m³

and density of ethanol is 789 kg/m³

so weight of water is = density × volume × g

put here value and we take g = 9.81

weight of water is = 997 × 0.45 × 9.81

weight of water = 4401.25 N     ......................1

weight of ethanol is = density × volume × g

put here value and we take g = 9.81

weight of ethanol is = 789 × 0.05 × 9.81

weight of ethanol = 387.00 N       ...............2

so total weight of liquid = sum of equation 1 add 2

total weight of liquid =  4401.25 + 387

total weight of liquid = 4788.25 N or 488.09 kg

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Answer:

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Explanation:

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