<span>To do this question, we need to know that momentum is conserved, meaning the overall velocity of the two balls has to be the same before and after the collision. </span>
<span>After collision... </span>
<span>Ball 1: 4.33m/s *cos 30 = 3.75 m/s (x-component) </span>
<span>4.33m/s * sin 30 = 2.165 m/s ( y-component) </span>
<span>Ball 2 (struck ball): 5 m/s - 3.75m/s = 1.25 m/s (x-component) </span>
<span>-2.165 m/s (y-component) note: it has to be in the opposite direction to conserve momentum </span>
<span>tan-1(2.165/1.25) = 60 degrees </span>
<span>Struck ball's velocity = sqrt(1.25^2 + 2.165^2) = 2.5 m/s at 60 degree with respect to the original line of motion. </span>
<span>Hope you understand!</span>
Answer:
I would say since it is still water the stream flow is 0km/h. Especially because he needs the same time upstream as He does down stream.
Answer: The net force is the vector sum of all the forces acting on an object. When an object is in equilibrium (either at rest or moving with constant velocity), the net force acting on it zero. A vector can only have zero magnitude if all of its components are zero. there is more than one force acting on an object, then F is the net force. If two people pull on an object with equal forces in opposite directions, then the net force is zero and the acceleration is zero
Explanation:
Answer:
Toward the centre of the circular path
Explanation:
The can is moved in a circular path: this means that it is moving by circular motion (uniform circular motion if its tangential speed is constant).
In order to keep a circular motion, an object must have a force that pushes it towards the centre of the circular trajectory: this force is called centripetal force, and its magnitude is given by

where m is the mass of the object, v its tangential speed, r the radius of the trajectory. This force always points towards the centre of the circular path.
Answer:
These are all the forces acting on the ball: friction, gravity, and a normal force.
Explanation: