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3 years ago

Why is physics an important part of history

Physics

2 answers:

tigry1 [53]3 years ago

8 0

Answer:

History and physics are intertwined through all the revolutionary thinkers, scientists, and people who studied these ideas. For example, many historical thinkers such as Isaac Newton and Galileo Galilei not only had revolutionary ideas, but they also changed life forever as the people knew it. It shocked the people and taught them new things, and upset the church.

Explanation:

Lorico [155]3 years ago

4 0

History is often disregarded in the study of physics, yet it is inherently connected to scientific inquiry through documentation of theory and subject matter through time. Scientific figures throughout history often serve as role models and examples for future physicists as well. Dredging up the history textbooks may seem like an absurd way to advance science, but consider: History involves ideas, theories, and equations that become the foundation for future improvements. Here are six reasons why understanding the history of physics could be useful to physicists and future physicists alike.

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Which of the following properties is the same for all electromagnetic radiation in a vacuum?

Crazy boy [7]

It is wavelength i think so!!!!

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3 years ago

A 0.877 mol sample of N2(g) initially at 298 K and 1.00 atm is held at constant volume while enough heat is applied to raise the

MissTica

Answer : The value of $q\text{ and }\Delta U$ is 286.2 J and 286.2 J respectively.

Explanation : Given,

Moles of sample = 0.877 mol

Change in temperature = 15.7 K

First we have to calculate the heat absorbed by the system.

Formula used :

$q=n\times c_v\times \Delta T$

where,

q = heat absorbed by the system = ?

n = moles of sample = 0.877 mol

$\Delta T$ = Change in temperature = 15.7 K

$c_v$ = heat capacity at constant volume of $N_2$ (diatomic molecule) = $\frac{5}{2}R$

R = gas constant = 8.314 J/mol.K

Now put all the given value in the above formula, we get:

$q=0.877mol\times \frac{5}{2}\times 8.314J/mol.K\times 15.7K$

$q=286.2J$

Now we have to calculate the change in internal energy of the system.

$\Delta U=q+w$

As we know that, work done is zero at constant volume. So,

$\Delta U=q=286.2J$

Therefore, the value of $q\text{ and }\Delta U$ is 286.2 J and 286.2 J respectively.

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3 years ago

A sample of an unknown substance has a mass of 89.5 g. If 345.2 J of heat are required to heat the substance from 285 K to 305 K

Zinaida [17]

Heat gained in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:<span>

Heat = mC(T2-T1)
345.2 = 89.5(C)(305 - 285)
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Describe and name the different types of collision. In which are the linear momentum and kinetic energy conserved

ipn [44]

Answer:

1. Elastic collision

2. Inelastic collision

Explanation:

Elastic collision: collision is said to be elastic if total kinetic energy is not conserved and if there is a rebound after collision

the collision is described by the equation bellow

$m1U1+ m2U2= m1V1+m2V2$

Inelastic collision: this type of collision occurs when the total kinetic energy of a body is conserved or when the bodies sticks together and move with a common velocity

the collision is described by the equation bellow

$m1U1+ m2U2= V(m1+m2)$

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