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3 years ago

23. Explain how the particles move before, during, and after melting.

Physics

1 answer:

Ket [755]3 years ago

3 0

Answer:

Answer: Option (D) is the correct answer.

Explanation:

Before placing the spoon in a hot liquid, particles of spoon were closer to each other and vibrating at their respective positions.

But when the spoon is placed in a hot liquid then due to increase in temperature of spoon its particles gain kinetic energy. Therefore, they colloid more frequently.

Thus, we can conclude that switch the labels on the diagrams best explains how to correct Alana’s error.

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A fixed mass of an ideal gas is heated from 50 to 80℃ at a constant pressure of (a) 1 atm and (b) 3 atm. for which case do you t

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3 years ago

What is a point of view of an object used to determine another object's motion

Finger [1]

<h2><em>A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. You assume that the reference point is stationary, or not moving.</em></h2>

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3 years ago

Mr. Barcena reached a top speed of 5m/s in 2 seconds from rest, what was his average acceleration including units?

sashaice [31]

Answer:

Explanation:

The equation for acceleration is

$a=\frac{v_f-v_0}{t}$ where vf is the final velocity and v0 is the initial velocity. Filling in:

$a=\frac{5-0}{2}$ so

a = 2.5 m/s/s

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3 years ago

Two electrons in a vacuum exert force of F = 3.8E-09 N on each other. They are then moved such that they are separated by x = 8.

iren [92.7K]

Answer:

F_n = 5.65E-11 N

d = 1.20682E-31 m

Explanation:

F = 3.8E-09 N

where

m = Mass of electron = 9.109E−31 kilograms

G = Gravitational constant = 6.67E-11 m³/kgs²

x = Distance between them

$F=G\frac{m^2}{x^2}\\\Rightarrow 3.8E-09=G\frac{m^2}{x^2}$

For $F_n$

$F_n=G\frac{m^2}{x^2}\\\Rightarrow F_n=G\frac{m^2}{(8.2x)^2}\\\Rightarrow F_n=G\frac{m^2}{67.24x^2}$

Dividing the above equations we get

$\frac{F}{F_n}=\frac{G\frac{m^2}{x^2}}{G\frac{m^2}{67.24x^2}}\\\Rightarrow \frac{F}{F_n}=67.24\\\Rightarrow F_n=\frac{F}{67.24}\\\Rightarrow F_n=\frac{3.8E-09}{67.24}\\\Rightarrow F_n=5.65E-11\ N$

F_n = 5.65E-11 N

$F=G\frac{m^2}{x^2}\\\Rightarrow x=\sqrt{\frac{Gm^2}{F}}\\\Rightarrow x=\sqrt{\frac{G}{F}}m\\\Rightarrow x=\sqrt{\frac{6.67E-11}{3.8E-09}}9.109E-31\\\Rightarrow x=1.20682E-31\ m$

d = 1.20682E-31 m

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Do heavier bowling balls go faster than lighter ones?

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