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3 years ago

What happenes when bromine reacted with aluminum?

1 answer:

4 0

Aluminum is a metal and reacts violently with all halogen elements, including bromine. ... As can be observed from the reaction enthalpy, the reaction is highly exothermic and a large amount of energy is released during the aluminum(III) bromide synthesis.

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How many moles are equal to 4.15x10^23 molecules of carbon monoxide?

Rudiy27

To be able to determine the number of moles that a certain number of molecules comprises, we simply divide the number of molecules by the Avogadro's number which is equal to 6.022 x 10^23.

n = M/A

where n is the number of moles, M is the number of molecules, and A is Avogadro's number. Substituting the known values,

n = (4.15 x 10^23 molecules)/(6.022 x 10^23 molecules/mol)

Simplifying,

n = 0.689 moles

<em>Answer: 0.689 moles</em>

7 0

3 years ago

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To what volume should you dilute 60.0 mL of a 4.50 M KI solution so that 30.0 mL of the diluted solution contains 3.25 g of KI?

SpyIntel [72]

Answer:

You should dilute to 414.1 mL

Explanation:

Let's apply the dilution formula to solve this:

M conc . Vol conc = M dil . Vol dil

Molarity for concentrated solution → 4.50 M

Volume for concentrated solution → 60 mL

Molarity for diluted solution → Unknown

Volume for diluted solution → Answer

Let's determine the molarity for diluted solution with data given.

We convert the mass of KI to moles

3.25 g . 1 mol/166 g = 0.0195 moles

Let's convert the volume from mL to L

30 mL . 1 L/1000mL = 0.030 L

Molarity (mol/L) = 0.0195 mol /0.030L = 0.652 M

We replace the data in the formula

4.50 M . 60 mL = 0.652 M . Volume for diluted solution

(4.50M . 60mL) / 0.652M = Volume for diluted solution

414.1 mL = Volume for diluted solution

7 0

3 years ago

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Phenol, c6h5oh, is a stronger acid than methanol, ch3oh, even though both contain an o]h bond. Draw the structures of the anions

timurjin [86]

In resonance structures, the chemical connectivity in the molecule is same but the distribution of electrons are different around the structure. They are created by moving electrons in double or triple bonds, and not atoms.

Phenol, $C_6H_5OH$ and methanol, $CH_3OH$ both are alcohols that contain an $-OH$ group attached to carbon atom.

Due to loss of 1 $H$ from phenol, it forms phenoxide anion and due to presence of double bond in the benzene ring the negative charge on the oxygen atom (which represents electrons) will resonate with double bonds of benzene ring as shown in the image. The resonance-stabilized phenoxide ion is more stable. Whereas when methanol lose 1 $H$ it forms methoxide anion and there are no such electrons present in the structure of methoxide that will result in the movement of electron. Since, due to resonance-stabilized phenoxide ion is more stable than methoxide ion, so it is a stronger acid.

The structures of the anions resulting from loss of 1 $H$ from phenol and methanol is shown in the image.

8 0

3 years ago

Synthesis gas consists of a mixture of H2 and CO. Calculate at 101kpa is compressed at constant temperature from 7.20 dm3 to 4.2

bazaltina [42]

Answer:

The final pressure is 173 kPa.

Explanation:

A mixture of gases at an initial pressure of P₁ = 101 kPa is compressed from an initial volume V₁ = 7.20 dm³ to a final volume V₂ = 4.21 dm³. If we suppose an ideal gas behavior and that temperature remains constant, we can apply Boyle's law to find out the final pressure P₂:

P₁ . V₁ = P₂ . V₂

$P_{2}=\frac{P_{1}.V_{1}}{V_{2}}=\frac{101kPa.7.20dm^{3} }{4.21dm^{3} } =173kPa$

5 0

4 years ago

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What volume would 3.01•1023 molecules of oxygen gas occupy at STP?

frosja888 [35]

<h3>Answer:</h3>

Volume = 11.2 L

<h3>Explanation:</h3>

Step 1: Calculate Moles:

As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Particles and Avogadro's Number is given as,

Number of Moles = Number of Particles ÷ 6.022 × 10²³

Putting values,

Number of Moles = 3.01× 10²³ Particles ÷ 6.022 × 10²³

Number of Moles = 0.50 Moles

Step 2: Calculate Volume:

As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ volume.

When 1 mole gas occupies 22.4 dm³ at STP then the volume occupied by 0.50 moles of gas is calculated as,

= (22.4 dm³ × 0.50 moles) ÷ 1 mole

= 11.2 dm³ ∴ 1dm³ = 1 L

So,

Volume = 11.2 L

4 0

4 years ago

Read 2 more answers