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OleMash [197]
3 years ago
11

If someone is suffering from the problem of acidity after overeating, which of the following would you suggest as remedy ?

Chemistry
1 answer:
kolezko [41]3 years ago
6 0

Answer:

nth

Explanation:

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Many atomic dimensions are expressed in angstroms (A). (1A = 1 x 10-8cm). What is the angstrom equal to in terms of the SI units
Nataly [62]

Answer:

1 Å = 1.0 × 10⁻¹ nm

1 Å = 1.0 × 10² pm

Explanation:

Angstrom is the unit of the length which is equal to one ten-billionth of the metre or 10⁻¹⁰ m. It is represented by the symbol is Å .

Angstrom is not part of SI system of the units, but it is considered as a part of metric system.  

Angstrom is used often in natural sciences as well as technology in order to express the sizes of atoms / molecules, and the lengths of the chemical bonds, etc.

1 Å = 10⁻¹⁰ m

1 nm = 10⁻⁹ m

1 pm = 10⁻¹² m

So,  

1 Å = 1.0 × 10⁻¹ nm

1 Å = 1.0 × 10² pm

7 0
3 years ago
A buffer solution contains 0.240 M ammonium chloride and 0.499 M ammonia. If 0.0565 moles of perchloric acid are added to 250 mL
snow_lady [41]

Answer:

The pH of the resulting solution is 9.02.

Explanation:

The initial pH of the buffer solution can be found using the Henderson-Hasselbalch equation:

pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})  

pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.240}{0.499}) = 4.43        

pH = 14 - pOH = 14 - 4.43 = 9.57

Now, the perchloric acid added will react with ammonia:

n_{NH_{3}} = 0.499moles/L*0.250 L - 0.0565 moles = 0.0683 moles

Also, the moles of ammonium chloride will increase in the same quantity according to the following reaction:

NH₃ + H₃O⁺ ⇄ NH₄⁺ + H₂O    

n_{NH_{4}Cl} = 0.240 moles/L*0.250L + 0.0565 moles = 0.1165 moles

Finally, we can calculate the pH of the resulting solution:

pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})  

pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.1165 moles/0.250 L}{0.0683 moles/0.250 L}) = 4.98  

pH = 14 - 4.98 = 9.02

Therefore, the pH of the resulting solution is 9.02.

I hope it helps you!

5 0
3 years ago
How many moles of hydrogen sulfide are contained in a 77.7-8 sample of this gas?
valentina_108 [34]

Answer:

its either C or D my guess is C though because 35.0g of hyddrogen is =1.03 mol

Explanation:

7 0
3 years ago
What is the molarity of a solution that has 2.52 grams of NaCO3 dissolved to
sammy [17]

Answer:

Explanation:

2.52g/ 0.125L= 20.16M

5 0
2 years ago
2. During asexual reproduction in paramecia, a single paramecium becomes two new
zloy xaker [14]

Answer:

ion no

Explanation:

ion no

4 0
3 years ago
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