Your answer is mass and speed! Please give me brainlist :)
Answer:
c. 15 g Kr
Explanation:
The amount of a gas (Moles) is directely proportional to its pressure. That means the higher amount of moles, the highest pressure and vice versa.
Using molar mass of the compounds (Ne=20.2g/mol, Ar = 39.9g/mol, Kr = 83.8g/mol, CO₂ = 44 g/mol and F₂ = 38.0g/mol), moles of 15.0g of each gas are:
Ne = 15g ₓ (1mol / 20.2g) = <em>0.74 moles of Ne</em>
Ar = 15g ₓ (1mol / 39.9g) = <em>0.38 moles of Ar</em>
Kr = 15g ₓ (1mol / 83.8g) = <em>0.18 moles of Kr</em>
CO₂ = 15g ₓ (1mol / 44g) = <em>0.34 moles of CO₂</em>
F₂ = 15g ₓ (1mol / 38g) = <em>0.39 moles of F₂</em>
<h3>As 15g of Kr contains the less quantity of moles, this sample will con have the lowest pressure</h3>
Covalent bond is the term that is being used to describe the bonds in the compounds that are created due to the sharing of one or more electrons. One of the best example of the simplest covalent bond is the bond that is being created when two isolated hydrogen atoms come together to form an H2 molecule. An isolated hydrogen atom has one proton and electron being combined by the force of attraction from the opposite-charged articles. When a pair of isolated hydrogen atom combines, two forces of attraction are created coming from each of the isolated hydrogen atom.
Answer:
The answer to your question is 88.7 ml
Explanation:
Data
Volume = ?
Concentration of NaOH = 0.142 M
Volume of H₂C₄H₄O₆ = 21.4 ml
Concentration of H₂C₄H₄O₆ = 0.294 M
Balanced chemical reaction
2 NaOH + H₂C₄H₄O₆ ⇒ Na₂C₄H₄O₆ + 2H₂O
1.- Calculate the moles of H₂C₄H₄O₆
Molarity = moles/volume
Solve for moles
moles = Molarity x volume
Substitution
moles = 0.294 x 21.4/1000
Result
moles = 0.0063
2.- Use proportions to calculate the moles of NaOH
2 moles of NaOH ------------------ 1 moles of H₂C₄H₄O₆
x ------------------ 0.0063 moles
x = (0.0063 x 2) / 1
x = 0.0126 moles of NaOH
3.- Calculate the volume of NaOH
Molarity = moles / volume
Solve for volume
Volume = moles/Molarity
Substitution
Volume = 0.0126/0.142
Result
Volume = 0.088 L or 88.7 ml
NH3 = 14 +3*1=17 g/mol
Mass = mol * molar mass = 0.687 * 17= 11.679 g
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