Question

How many atoms of carbon are in 0.425 g of ibuprofen?

Answer 1

Answer is: 1,6·10²².
Molecular formula of ibuprofen is C₁₃H₁₈O₂.
m(C₁₃H₁₈O₂) = 0,425 g.
n (C₁₃H₁₈O₂) = m(C₁₃H₁₈O₂) ÷ m(C₁₃H₁₈O₂)
n(C₁₃H₁₈O₂) = 0,425g ÷206,3 g/mol = 0,002mol.
n(C) : n(C₁₃H₁₈O₂) = 13 : 1
n(C) = 0,026 mol.
N(C) = n(C) · Na = 0,026 mol · 6·10²³ 1/mol = 1,6·10²².
Na - Avogadro number.

Answer 2

Explanation:

It is known that the chemical formula of Ibuprofen is $C_{13}H_{18}O_{2}$.

According to Avogadro, 1 mole of an atom contains $6.022 \times 10^{23}$ atoms.

As molar mass of Ibuprofen is 206.29 g/mol. So, number of moles of ibuprofen will be calculated as follows.

            No. of moles = $\frac{mass}{\text{molar mass}}$

                                  = $\frac{0.425 g}{206.29 g/mol}$

                                  = $2.06 \times 10^{-3}$ mol

Since. there are 13 atoms of carbon present in a molecule of ibuprofen. Hence, total atoms of carbon present in $2.06 \times 10^{-3}$ mol of Ibuprofen will be as follows.

       $2.06 \times 10^{-3} mol \times 13 \times 6.022 \times 10^{23}$

         = $0.161 \times 10^{23}$ atoms

Thus, we can conclude that there are $0.161 \times 10^{23}$ atoms of carbon are in 0.425 g of ibuprofen.