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Butoxors [25]
3 years ago
7

For the following chemical reactions, determine the precipitate produced when the two reactants listed below are mixed together.

Note: Leave the answer blank if no precipitate will form. (Express your answer as a chemicalformula.) 1. Ba(NO3)2(aq) + MgSO4(aq)→ 2. HNO3(aq) + Ba(OH)2(aq)→ 3. KCl(aq) + AgNO3(aq)→ 4. (NH4)3PO4(aq) + Ni(NO3)2(aq)→ 5. Na2CO3(aq) + NH4Cl(aq)------->
Chemistry
1 answer:
Free_Kalibri [48]3 years ago
8 0
Ba(Oh)2(aq) + KCI(aq)>
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Which two types of consumers are known as “nature’s clean-up crew”? Why are they important?
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Fungus: Important because it breaks up several dead leaves, particles, etc, and puts nutrients back in the ground.

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3 years ago
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If 50 ml of 0.235 M NaCl solution is diluted to 200.0 ml what is the concentration of the diluted solution
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This is a straightforward dilution calculation that can be done using the equation

M_1V_1=M_2V_2

where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:

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Substituting in our values, we get

\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.

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