Answer:
82.4 cm
Explanation:
∑F = ma
kx cos θ = ma
x = ma / (k cos θ)
x = (10 kg) (5 m/s²) / (70 N/m cos 30.0°)
x = 0.824 m
x = 82.4 cm
Answer: 0.5 seconds or 2.625 seconds
Explanation:
At t = 0, The ball is 4 ft above the ground.
The height of the football varies with time in the following way:
s(t) = -16 t² + 50 t + 4
we need to find the time in which the height would of the football would be 25 ft:
⇒25 = -16 t² + 50 t + 4
we need to solve the quadratic equation:
⇒ 16 t² - 50 t + 21 = 0

⇒ t = 0.5 s or 2.625 s
Therefore, at t = 0.5 s or 2.625 s, the football would be 25 ft above the ground.
Answer:
No because you cannot see air so therefore it cannot make shadows
Explanation:
Good afternoon.
We have:

The function of velocity:

For
t = 5 s: