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Stels [109]
3 years ago
5

PLEASE HELP NOT A LOT OF TIME LEFT!!!!!

Physics
1 answer:
GenaCL600 [577]3 years ago
8 0
D. 65.1 is the answer
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Explain why you can only change one variable in an experiment
ohaa [14]
The purpose of an experiment is to LEARN the EFFECT of something.

The way you do that is to CHANGE the thing and see what happens.

You can change as many things as you want to.  But If you change
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of them caused the effect you see. 

Or maybe BOTH of them working together caused it.  You don't know. 

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5 0
3 years ago
What is the volume of an object that has a density of 65g/cm3 and a mass of 130g.
lora16 [44]

Density <em>ρ</em> is mass <em>m</em> per unit volume <em>v</em>, or

<em>ρ</em> = <em>m</em> / <em>v</em>

Solving for <em>v</em> gives

<em>v</em> = <em>m</em> / <em>ρ</em>

So the given object has a volume of

<em>v</em> = (130 g) / (65 g/cm³) = 2 cm³

5 0
3 years ago
Using the definition of moment of inertia, calculate icm, the moment of inertia about the center of mass, for this object.
Step2247 [10]
<span> The masses have no inertia about their own CM, and "the object" is the two masses. </span>
<span>1. Icm (at point A) = 2mr^2 
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3 0
3 years ago
A 0.75 kg book is pushed across the table with an acceleration of 0.3 m/s2. What force is being applied to the
Brums [2.3K]

Answer:

\boxed {\boxed {\sf 0.225 \ Newtons}}

Explanation:

We are asked to find the force being applied to a book. According to Newton's Second Law of Motion, force is the product of mass and acceleration.

F= ma

The mass of the book is 0.75 kilograms and the acceleration is 0.3 meters per square second. Substitute these values into the formula.

  • m= 0.75 kg
  • a= 0.3 m/s²

F= 0.75 \ kg * 0.3 \ m/s^2

Multiply.

F =0.225 \ kg * m/s^2

1 kilogram meter per second squared is equal to 1 Newton. Therefore, our answer of 0.225 kilogram meters per second squared is equal to 0.225 Newtons.

F= 0.225  \ N

<u>0.225 Newtons of force</u> are applied to the book.

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Why is the solar system commonly represented as a scale model?
topjm [15]
The actual size of the Solar system is too big to show without making a much smaller model. If someone wants to see the orientation of the planets a model has to be made so we can see it without flying out too space.
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