The value of the final speed depends on the mass of the ore.
Let's call m the mass of the ore. We can solve the exercise by requiring the conservation of momentum, which must be the same before and after the ore is loaded.
Initially, there is only the cart, so the momentum is

After the ore is loaded, the new mass will be (1200 kg+m), and the new speed is

. The momentum p is conserved, so it is still 12960 kg m/s. Therefore, we have

and so the final speed is
Answer:
Honestly for me it's a bit too blurry. Sorry luv.:(
Explanation:
<h2>
Answer:</h2>
<em>Hello, </em>
<h3><u>
QUESTION)</u></h3>
Assuming that the initial velocity of the jumper is zero, on Earth any freely falling object has an acceleration of 9.8 m/s².
<em>✔ We have : a = v/Δt = ⇔ Δt = v/a </em>
- Δt = (√2xgxh)/9,8
- Δt = (14√10)/9,8
- Δt ≈ 4,5 s
The correct answer is
<span>c) very small and very large
Let's see this with a few examples:
1) if we have a very small number, such as
</span>

<span>we see that we can write it easily by using the scientific notation:
</span>

<span>2) Similarly, if we have a very large number:
</span>

<span>we see that we can write it easily by using again the scientific notation:
</span>

<span>
</span>
2,450 Joules, kinetic energy is 1/2 mass x velocity squared.