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anzhelika [568]
3 years ago
7

the mass of one water drop is 0.0008kg and the gravitational field strength is 10N/kg what is its weight

Physics
1 answer:
djyliett [7]3 years ago
8 0
Weight = (mass) x (gravity)

Weight = (8 x 10⁻⁴ kg) x (10 N/kg) = 0.008 Newton
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Consider the uniform electric field \vec{E} =(4.00~\hat{j}+3.00~\hat{k})\times 10^3~\text{N/C} ​E ​⃗ ​​ =(4.00 ​j ​^ ​​ +3.00 ​k
Tema [17]

Answer:

Electric flux, \phi=6.668\times 10^4\ Nm^2/C

Explanation:

It is given that,

Electric field, E=(4j+3k)\times 10^3\ N/C

We need to find the electric flux through a circular area of radius 2.66 m that lies in the xy-plane. A=Ak

The electric flux is given by :

\phi=E{\cdot}A

\phi=(4j+3k)\times 10^3{\cdot}Ak

Since, k.k=i.i=j.j = 1

So,

\phi=3\times 10^3\times \pi\times (2.66)^2\ k

\phi=6.668\times 10^4\ Nm^2/C

So, the electric flux through a circular area is \phi=6.668\times 10^4\ Nm^2/C.Hence, this is the required solution.

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gogolik [260]

Answer:

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2 years ago
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Answer:

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What is the mass of a crate if a net force of 12 N gives the crate an acceleration of 0.20 m/s2?
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F = ma
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