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3 years ago

If the pendulum took longer to complete one oscillation, how would the graph change?

Physics

2 answers:

Sindrei [870]3 years ago

7 0

Answer:

took longer to complete one oscillation, that means its PERIOD increased, and the distance between the peaks of the graph would be longer.

line would be less. the period of oscillation would have any effect on the graph

Komok [63]3 years ago

6 0

Answer: The distance between peaks would be longer.

Explanation:

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Suppose you have a 115 kg wooden crate resting on a wood floor, with coefficient of static friction 0.500 between these wood sur

alexdok [17]

Answer:

maximum force (in N) can you exert horizontally on the crate without moving it = 564.075 N

Explanation:

Given data:

mass m= 115 kg

coefficient of friction μ =0.5

according to newton law of motion the net force acted on body is given by

$F_{net}=ma=F_{max}- F_{f}$

here the body is in rest ,

$F_{net}=0\\\Rightarrow F_{max}=F_{f}\\\text{frriction force} F_{f} = \mu\times N\\$

N= it is the normal reaction force

N= mg = 115×9.81

therefore,

$F_{f} = 0.5\times115\times9.81 = 564.075 N = F_{max}$

4 0

3 years ago

A bird has a mass of 0.8 kg and flies at a speed of 11.2 m/s. How much kinetic energy does the bird have?

riadik2000 [5.3K]

The kinetic energy of an object is directly proportional to its mass and the square of its velocity

KE = 1/2 (mv²)

KE = Kinetic Energy
m = mass in kg
v = velocity in m/s

Given:

m = .8 kg
v = 11.2 m/s

Substitute:

KE = 1/2 (.8)(11.2²)
KE = 50.18 J

7 0

3 years ago

Read 2 more answers

A projectile is fored vertically upward with an initial velocity of 190 m/s. Find the maximum height of the projectile.

RSB [31]

Answer:

3683.67 m

Explanation:

Formula for maximum height of projectile is given by the equation;

h = u²/2g

Where u is initial velocity and g is acceleration due to gravity

We are given u = 190 m/s

Thus;

h = 190²/9.8

h = 36100/9.8

h = 3683.67 m

6 0

3 years ago

A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what d

oksano4ka [1.4K]

Answer:

x = 45 cm

Explanation:

Given that,

The length of a rod, L = 50 cm

Mass, m₁ = 0.2 kg

It is at 40cm from the left end of the rod.

We need to find the distance from the left end of the rod should a 0.6kg mass be hung to balance the rod.

The centre of mass of the rod is at 25 cm.

Taking moments of both masses such that,

$15\times 0.2=x\times 0.6\\\\x=\drac{3}{0.6}\\\\x=5\ cm$

The distance from the left end is 40+5 = 45 cm.

Hence, at a distance of 45 cm from the left end it will balance the rod.

5 0

3 years ago

Which statement is correct

daser333 [38]

C Weight is the gravitational pull on an object

8 0

3 years ago