A: C₆H₁₂O₆ + 6H₂O + 6O₂
6CO₂ + 12H₂O = C₆H₁₂O₆ + 6H₂O + 6O₂
Answer:
The answer is
<h2>112.912 kPa</h2>
Explanation:
The new pressure can be found by using the formula for Boyle's law which is
Since we are finding the new pressure
404.6 kPa = 404600 Pa
From the question we have
We have the final answer as
<h3>112.912 kPa</h3>
Hope this helps you
Answer:
There is 52.33 grams of water produced.
Explanation:
Step 1: Data given
Mass of propane burned = 32.00 grams
Molar mass of propane = 44.1 g/mol
Oxygen is in excess
Molar mass of water = 18.02 g/mol
Step 2: The balanced equation
C3H8 + 5O2 → 4H2O + 3CO2
Step 3: Calculate moles of propane
Moles of propane = mass propane / molar mass of propane
Moles of propane = 32.00 grams / 44.1 g/mol
Moles of propane = 0.726 moles
Step 4: Calculate moles of H2O
Propane is the limiting reactant.
For 1 mol of propane consumed, we need 5 moles of O2 to produce 4 moles of H2O and 3 moles of CO2
For 0.726 moles of propane we'll have 4*0.726 = 2.904 moles of H2O
Step 5: Calculate mass of H2O
Mass of H2O = moles of H2O * molar mass of H2O
Mass of H2O = 2.904 moles * 18.02 g/mol
Mass of H2O = 52.33 grams
There is 52.33 grams of water produced.
is an outer shell electron that is associated with an atom
The heat released/absorbed by a reaction that occurs at constant pressure.
Hope this helped :)
