The atoms that would be expected to be diamagnetic in the ground state is magnesium
The magnetism of an atom refers to its electronic configuration. A diamagnetic atom is an atom whose electrons are all paired.
A paired electron is an electron that occurs in pairs in its orbital shell.
At their respective ground state, the electronic configuration of the given elements are as follows:
The electronic configuration of magnesium is 1s²2s²2p⁶3s². As such its a diamagnetic atom.
The electronic configuration of Potassium is 1s²2s²2p⁶3s²3p⁶4s¹. Hence, Potassium has one unpaired electron in its outermost shell.
The electronic configuration of Chlorine is 1s²2s²2p⁶3s²3p⁵. Hence, Chlorine has one unpaired electron in its outermost shell.
The electronic configuration of Cobalt is 1s²2s²2p⁶3s²3p⁶3d⁷4s². Hence, the unpaired electrons of Cobalt in its outermost shell are three.
Therefore, the atoms that are diamagnetic in the ground state is magnesium.
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I believe the correct answer is 2340g of a particular substance will be dissolved in 650 L of H2O. Hope I was helpful in some way. Thanks. Peace.
Since intermolecular forces is stronger in a solid than a liquid, then NaCl has stronger intermolecular forces than H2O.
Intermolecular forces exists between molecules of the same or different kinds. Water has a dipole moment hence it can interact effectively with the ions in NaCl. This leads to an ion dipole interaction that results in the dissolution of NaCl in H2O.
NaCl is a solid and water is a liquid. Since intermolecular forces is stronger in a solid than a liquid, then NaCl has stronger intermolecular forces than H2O.
Hence, the best argument that compares the intermolecular interactions in water and NaCl is; salt is a solid and water is a liquid, so water has stronger intramolecular forces.
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It would be known as a meth_(insert - ane, - ene, and -yne) hydrocarbon.
1 bond = -ane
2 bonds = - ene
And so on.
Answer:
The answer to your question is Pressure = 5 atm
Explanation:
Data
Volume 1 = V1 = 0.5 l
Pressure 1 = P1 = 1 atm
Volume 2 = V2 = 0.1 l
Pressure 2 = P2 = x
Formula
To solve this problem use the Boyle's equation
V1P1 = V2P2
Solve for P2
P2 = V1P1/V2
Substitution
P2 = (0.5 x 1) / 0.1
Simplification
P2 = 0.5/0.1
Result
P2 = 5 atm