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Kipish [7]
3 years ago
13

The octet rule states that the formula for a compound is derived by Group of answer choices having a net charge of magnitude 8.

using a minimum of 8 atoms. using exactly 8 bonds in the formula unit. having all atoms or ions get noble gas electron configurations.
Chemistry
1 answer:
balandron [24]3 years ago
6 0

Answer:

Atoms bonds with 8 electrons

Explanation:

Octet rule is a chemical rule that shows elements in main group bond so that each atom have 8 valence electrons in the outmost shell which make them to have similar electronic configuration with Noble gases This is important because the sharing of electrons make atoms to have full shell. Atoms with electrons not up to 8 react with more stable compound.

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10.0 g of Mg(NO3)2 = ____ moles
JulsSmile [24]

Answer:

0.067424154568526 moles

6 0
3 years ago
How to draw Hess' Cycle for this question ?
NISA [10]

Answer : The standard enthalpy of formation of ethylene is, 51.8 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of C_2H_4 will be,

2C(s)+2H_2(g)\rightarrow C_2H_4(g)    \Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

(1) C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)     \Delta H_1=-1411kJ/mole

(2) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_2=-393.7kJ/mole

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_3=-285.9kJ/mole

Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equations, we get :

(1) 2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g)     \Delta H_1=+1411kJ/mole

(2) 2C(s)+2O_2(g)\rightarrow 2CO_2(g)    \Delta H_2=2\times (-393.7kJ/mole)=-787.4kJ/mole

(3) 2H_2(g)+2O_2(g)\rightarrow 2H_2O(l)    \Delta H_3=2\times (-285.9kJ/mole)=-571.8kJ/mole

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(+1411kJ/mole)+(-787.4kJ/mole)+(-571.8kJ/mole)

\Delta H=51.8kJ/mole

Therefore, the standard enthalpy of formation of ethylene is, 51.8 kJ/mole

7 0
2 years ago
"Do you own a dog?" might be an example of which concept?
Anna11 [10]

C: Control Question

Have a good day :)

6 0
3 years ago
Which of the following describe a noble gas?
shutvik [7]
The correct answer is B. Low chemical reactivity
7 0
2 years ago
What bonds of the reactants are broken in this reaction? What bonds are formed in the product?
Y_Kistochka [10]
<span>Bonds of reactants are broken and create new bonds to form different products and produces exothermic and endothermic reactions.
You are able to see a chemical reaction occur through a few signs
hope this helps

</span>
7 0
3 years ago
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