A Brayton cycle with regeneration using air as the working fluid has a pressure ratio of 7. The minimum and maximum temperatures
in the cycle are 310 and 1150 K. Assuming an isentropic efficiency of 75 percent for the compressor and 82 percent for the turbine and an effectiveness of 65 percent for the regenerator. Determine the total exergy destruction associated with the cycle, assuming u source temperature of 1500 K and a sink temperature of 290 K. Also, determine the exergy of the exhaust gases at the exit of the regenerator. Use variable specific heats for air.
1 answer:
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Answer:
1.6 m/s^2
Explanation:
Hello!
To calculate the acceleration we must know the electric field. The electric field and the potential are related by:
If the particle starts at 2.3m, the electric field is:
E = 36.869 V/m = 36.869 N/C
So, the force on the particle is:
F = q E = 2.3×10^−6 C * 36.869 N/C = 8.48 x 10^-5 N
And its acceleration is :
a = F/m = 8.48 x 10^-5 N / 5.4×10−5 kg = 1.57 m/s^2
Rounded to two significant figures:
1.6 m/s^2