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3 years ago

Someone pleaseeee help me I need it now

Chemistry

1 answer:

denis23 [38]3 years ago

4 0

Answer:

Personal Question

Explanation:

I wish I could help more, but it's based on your own prior knowledge, desires and experiences. Only you can answer those questions. For the first one, if you know examples of genetic engineering you could write that, or you could define it. For the second one, you could talk about things that interest you. The last one you could talk about the concepts you learned in the lesson and the things you didn't know before the lesson and then learned afterward. You could talk about the methods of genetic manipulation, or just what you learn in the class.

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Phthalates used as plasticizers in rubber and plastic products are believed to act as hormone mimics in humans. The value of ΔHc

jeka94

Answer:

$T_f$ = 25.05°C

Explanation:

Given:

the value of ΔHcomb (heat of combustion) for dimethylphthalate (C10H10O4) is = 4685 kJ/mol.

mass = 0.905g of dimethylphthalate

molar mass = 194.18g dimethylphthalate

number of moles of dimethylphthalate = ???

$T_i$ = 21.5°C

$C_{calorimeter}$ = 6.15 kJ/°C

$T_f$ = ???

since we have our molar mass and mass of dimethylphthalate ;we can determine the number of moles as;

0.905g of dimethylphthalate × $\frac{1 mole (dimethylphthalate)}{194.184g(dimethylphthalate)}$

number of moles of dimethylphthalate = 0.000466 moles

Heat released = moles of dimethylphthalate × heat of combustion

= 0.000466 moles × 4685 kJ

= 21.84 kJ

∴ Heat absorbed by the calorimeter = $C_{calorimeter}$ $(T_f-T_i} )$

21.84 kJ =6.15 kJ/°C $* (T_f-21,5^0C)$

21.84 KJ = $(6.15 kJ/^0C * T_f) - (6.15 kJ/^0C*21.5^0C)$

21.84 KJ = $(6.15 kJ/^0C * T_f)$ - 132.225 kJ

21.84 KJ + 132.225 kJ = $(6.15 kJ/^0C * T_f)$

154.065 kJ = $(6.15 kJ/^0C * T_f)$

$T_f$ = $\frac{154.065kJ}{6.15kJ/^0C}$

$T_f$ =25.05°C

4 0

3 years ago

Calculate the [oh] for 0.46 Hcl

Bad White [126]

Answer:

2.17 e -14

Explanation:

A strong acid like HCl ionize 100 % in water so [H3O+] = 0.46 M

[OH-] = Kw / [H3O+]

= 1.0 e -14 / 0.46

= 2.17 e -14

3 0

3 years ago

In each of the following blanks, only enter a numerical value.

tatiyna

Answer:

1) 1,... 2

2) 18

3) n= 3 and I=1

Explanation:

1) when l= 0, its an s-sub-level, and only 1 orbital is possible which can carry only 2-electrons

2) the maximum number of electron is given by 2n^2= 2×3^2= 18

3) in 3p, the coefficient of p is the value of n= 3 and l-value of P is 1

5 0

2 years ago

PLEASE ANSWER FAST DUE IN 2 MINUTES

mixer [17]

Answer:

Carbon dioxide gas

Explanation:

When an animal breathes, it takes in oxygen gas and releases carbon dioxide gas into the atmosphere.

5 0

2 years ago

Ethanol (C 2H 6O(l), ΔH o f = -277.69 kJ/mol) can be made by reaction of ethylene (C 2H 4(g) ΔH o f = 52.26 kJ/mol) with water (

lidiya [134]

Answer:

Enthalpy change = -44.12 kJ

Explanation:

Given:

ΔH°f(C2H6O(l)) = -277.69 kj/mol

ΔH°f(C2H4(g)) = 52.26 kj/mol

ΔH°f(H2O) = -285.83 kj/mol

To determine:

Enthalpy change for the formation of C2H6O

Calculation:

The given reaction is:

$C2H4(g) + H2O(g)\rightarrow C2H5OH(g)$

The enthalpy change for the reaction is given as;

$\Delta H = \sum n(products)\Delta H^{0}f(products)-\sum n(reactants)\Delta H^{0}f(reactants)$

where n(products) and n(reactants) are the moles of products and reactants

Substituting the appropriate values for n and ΔH°f:

$\Delta H = 1\Delta H^{0}f(C2H6O)-[1\Delta H^{0}f(C2H4)+1\Delta H^{0}f(H2O)]$

ΔH = -277.69-(52.26-285.83) = -44.12 KJ

4 0

3 years ago

Someone pleaseeee help me I need it now​

Someone pleaseeee help me I need it now