Answer:
570 N
Explanation:
Draw a free body diagram on the rider. There are three forces: tension force 15° below the horizontal, drag force 30° above the horizontal, and weight downwards.
The rider is moving at constant speed, so acceleration is 0.
Sum of the forces in the x direction:
∑F = ma
F cos 30° - T cos 15° = 0
F = T cos 15° / cos 30°
Sum of the forces in the y direction:
∑F = ma
F sin 30° - W - T sin 15° = 0
W = F sin 30° - T sin 15°
Substituting:
W = (T cos 15° / cos 30°) sin 30° - T sin 15°
W = T cos 15° tan 30° - T sin 15°
W = T (cos 15° tan 30° - sin 15°)
Given T = 1900 N:
W = 1900 (cos 15° tan 30° - sin 15°)
W = 570 N
The rider weighs 570 N (which is about the same as 130 lb).
Answer:
Law 1. A body continues in its state of rest, or in uniform motion in a straight line, unless acted upon by a force.
Law 2. A body acted upon by a force moves in such a manner that the time rate of change of momentum equals the force.
Law 3. If two bodies exert forces on each other, these forces are equal in magnitude and opposite in direction.
theanswer is b.heart disease
Answer:
11.23%
Explanation:
Lets take
Speed of man in still water =u= 1.73 m/s
Speed of flow of water = v=0.52 m/s
When swims in downward direction then speed of man = u + v
When swims in upward direction then speed of man = u - v
Lets time taken by man when he swims in downward direction is 
and when he swims in downward direction is 
Lets distance is d and it will be remain constant in both the case
Time taken in still water
2 d= t x 1.73
t=1.15 x d sec
total time in current = 0.82 +0.44 d=1.26 d sec
So the percentage time
Percentage time =11.32%
So it will take 11.32% more time as compare to still current.
Answer:
Explanation:
The average pressure at mean sea-level (MSL) in the International Standard Atmosphere (ISA) is 1013.25 hPa, or 1 atmosphere (atm), or 29.92 inches of mercury. Pressure (p), mass (m), and the acceleration due to gravity (g), are related by P = F/A = (m*g)/A, where A is surface area.
