Answer:
Ф6 = 3 Wb
Explanation:
the flux is positive when N is odd and positive when N is even so we can write the flux through the all side as
∑ N=1, to5
∑ -1 ^N Ф N * Ф6 =0
∑ -1 ^ N * Ф6 =0
Where :
ФN=N
Replacing and operated so
-1 Wb +2 Wb - 3 Wb + 4Wb - 5Wb + Ф6=0
Ф6 - 3Wb = 0
Ф6 = 3 Wb
Answer:
Height of the rocket be one minute after liftoff is 40.1382 km.
Explanation:
v = velocity of rocket at time t
g = Acceleration due to gravity =
= Constant velocity relative to the rocket = 2,900m/s.
m = Initial mass of the rocket at liftoff = 29000 kg
r = Rate at which fuel is consumed = 170 kg/s
Velocity of the rocket after 1 minute of the liftoff =v
t = 1 minute = 60 seconds'
Substituting all the given values in in the given equation:
Height of the rocket = h
Height of the rocket be one minute after liftoff is 40.1382 km.
Answer: The 1 kg fragment will have three times the speed of the 3kg fragment.
Explanation:Here for the bomb, its chemical energy gets converted into the mechanical energy.
According to the law of conservation of momentum, the two bodies will have equal momentum and to satisfy this condition the lighter mass will have the higher velocity.
∵ momentum, p = mass × velocity
∴The 1 kg fragment will have three times the speed of the 3kg fragment.
Answer:
107 seconds
Explanation:
Time taken to travel 1.5 Km at a speed of 85 km/h=
Time taken to travel 0.8 Km at a speed of 67 km/h =
Total distance= 1.5+0.8=2.3 km
Total time=0.017647059+0.011940299=0.029587357 hours
Converting hours to seconds, we multiply hours by 3600 hence total time=0.029587357*3600=106.5144864 seconds,
Rounding off, time=107 seconds