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Vesnalui [34]
3 years ago
13

The first chart shows the effect of the normal breakdown of material from reactants to products. The second chart shows the same

reaction but with an added modification.
Which statement best describes the difference between the charts?

Reaction A has an enzyme.
Reaction B has an enzyme.
Reaction A has an inhibitor.
Reaction B has an inhibitor.

Chemistry
2 answers:
Reika [66]3 years ago
8 0

Answer:

B

Explanation:

Reaction B has an enzyme

sashaice [31]3 years ago
5 0

Answer:

Reaction B has an enzyme.

Explanation:

In both charts, we can see the energy versus the progress of the reaction. In both charts, reactants and products have the same energy, but chart B has a lower activation energy (The difference in energy between the reactants and the activated complex). This is probably due to the action of an enzyme. Enzymes lower the activation energy in order to increase the reaction rate as we can see in the Arrhenius equation.

k=A.e^{-Ea/R.T}

where,

k is the rate constant

A is the collision factor

Ea is the activation energy

R is the ideal gas constant

T is the absolute temperature

The higher the rate constant, the higher the reaction rate.

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Answer:

Ksp = 2.74 x 10⁻⁵

Explanation:

The solubility equilibrium for Ca(OH)₂ is the following:

  Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)

I                          0                0

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According to the ICE table, the expression for the solubility product constant (Kps) is:

Ksp = [Ca²⁺] x ([OH⁻])² = s x (2s)² = 4s³

Then, we calculate Ksp from the solubility value (s):

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⇒ Ksp = 4s³ = 4 x (0.019)³ = 2.74 x 10⁻⁵

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In the important industrial process for producing ammonia (the Haber Process), the overall reaction is: N2(g) + 3H2(g) → 2NH3(g)
irakobra [83]
Answer is: <span>B) -50.2 kJ.

Balanced chemical reaction: </span>N₂(g) + 3H₂(g) → 2NH₃(g) ΔH = -<span>100.4 kJ.
This is exothermic reaction, because heat is released and energy is include as product of chemical reaction.
Make proportion, two moles of ammonia released 100.4 kJ of heat, then one mole of ammonia released:
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3 years ago
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kykrilka [37]

Answer:

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The catalyst has no effect whatsoever on the position of the equilibrium. Adding a catalyst doesn't produce any greater percentage of ammonia in the equilibrium mixture. Its only function is to speed up the reaction.

Explanation:

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