Answer:
a. Values are - (1) 3,1,-1,1/2 (2) 2,1,-1,-1/2 (3) 3,0,0,1/2 (4) 4,3,3,-1/2
(5) 3,2,2,1/2
b. Order be- I > Sn > Xe
Explanation:
a.
Valid quantum numbers are -
'l' value should be less than 'n' value and 'ml' value should be '-l' to 'l'
'ml' value should not more than 'l' or 'n'.
Values are -
3,1,-1,1/2
2,1,-1,-1/2
3,0,0,1/2
4,3,3,-1/2
3,2,2,1/2
b.
Given that-
I [Kr]4d¹⁰5s²5p⁵
Sn [Kr]4d¹⁰5s²5p²
Xe [Kr]4d¹⁰5s²5p⁶
Order be-
I > Sn > Xe
Xe is least because it is completely filled outer shell (5s²5p⁶
<span>6 + x = 12. To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.</span>
Answer: 1. Mass and type of solution
2. Type of material
3. Temperature
Atomic mass silicon = 28.085 u
1 mol Si ---------------- 28.085 g
? ------------------------ 245 g
245 x 1 / 28.085 =><span> 8.72 mol</span>
<span>answer A</span>
Answer:
![p[H+] = 10.042](https://tex.z-dn.net/?f=p%5BH%2B%5D%20%3D%2010.042)
Explanation:
As we know that
......eq (1)
we will calculate the pH of OH- and then we will calculate the pH of H+
So p[OH-] ![= - log [1.10 * 10^{-4}]](https://tex.z-dn.net/?f=%3D%20-%20log%20%5B1.10%20%2A%2010%5E%7B-4%7D%5D)
Solving the right side of the equation, we get
p[OH-]
![= - [-3.958]\\= 3.958](https://tex.z-dn.net/?f=%3D%20-%20%5B-3.958%5D%5C%5C%3D%203.958)
Now we know that

Substituting the value of pOH in the above equation, we get -
![14.0 = p[H+] + 3.958\\p[H+] = 14 - 3.958\\p[H+] = 10.042](https://tex.z-dn.net/?f=14.0%20%3D%20p%5BH%2B%5D%20%2B%203.958%5C%5Cp%5BH%2B%5D%20%3D%2014%20-%203.958%5C%5Cp%5BH%2B%5D%20%3D%2010.042)