If we react 30 grams of ethane (C2H6 ) with 320 grams of oxygen, how many grams of carbon dioxide would we make
1 answer:
The mass of carbon dioxide that would be made by reacting 30 grams C2H6 with 320 grams O2 will be 80 grams
From the balanced equation of the reaction:
The mole ratio of C2H6 to O2 is 2:7.
- Mole of 30 grams C2H6 = mass/molar mass
= 30/30
= 1 mole
- Mole of 320 grams O2 = 320/32
= 10 moles
Thus, C2H6 is the limiting reactant.
Mole ratio of C2H6 to CO2 according to the equation = 1:2
Since the mole of C2H6 is 1, the equivalent mole of CO2 would, therefore, be 2.
Mass of 2 moles CO2 = mole x molar mass
= 2 x 44
= 88 grams
More on stoichiometric calculations can be found here: brainly.com/question/8062886?referrer=searchResults
You might be interested in
Answer: m= 1.02x10² g AlCl3 or 1091.3 g AlCl3
Explanation: solution attached.
Convert mass of Mg to moles
Do the mole ratio between Mg and AlCl3 based from the balanced equation.
Convert moles of AlCl3 to mass using its molar mass.
