The grams of ethane present in a sample containing 0.4271 mole is 12.84 g
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation
Mole = mass / molar mass
With the above formula, we can obtain the mass of ethane. Details below
<h3>How to determine the mass of ethane</h3>
The following data were obtained from the question:
- Mole of ethane = 0.4271 mole
- Molar mass of ethane = 30.067 g/mol
- Mass of ethane =?
The mass of ethane present in the sample can be obtained as follow:
Mole = mass / molar mass
Cross multiply
Mass = mole × molar mass
Mass of ethane = 0.4271 × 30.067
Mass of ethane = 12.84 g
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C6H12O6 molar mass: 180.15768 g
solute: sugar
molarity = moles of solute / liters of solution
Jones Soda:
33 g / 180.15768 g = 0.18 moles C6H12O6
M = 0.18 g / 0.355 L
M = 0.52
Sierra Mist:
62 g / 180.15768 g = 0.34 moles C6H12O6
M = 0.34 g / 0.591 L
M = 0.58
Sienna Mist has a higher molarity and is more concentrated.
Answer:
1
Explanation:
4 HBr + O2 → 2H 20 + 2Br 2
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