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nirvana33 [79]
3 years ago
5

The molar solubility of C a ( O H ) 2 C a ( O H ) 2 was experimentally determined to be 0.019 M. Based on this value, what is th

e K s p K s p of C a ( O H ) 2 C a ( O H ) 2 ?
Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

Ksp = 2.74 x 10⁻⁵

Explanation:

The solubility equilibrium for Ca(OH)₂ is the following:

  Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)

I                          0                0

C                       + s               + 2s

E                        s                   2s

According to the ICE table, the expression for the solubility product constant (Kps) is:

Ksp = [Ca²⁺] x ([OH⁻])² = s x (2s)² = 4s³

Then, we calculate Ksp from the solubility value (s):

s = 0.019 M

⇒ Ksp = 4s³ = 4 x (0.019)³ = 2.74 x 10⁻⁵

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Answer:

Yes, it is possible.

Explanation:

A diprotic acid is an acid that can release two protons. That's why it is called diprotic.

Monoprotic → Release one proton, for example Formic acid HCOOH

Triprotic → Releases three protons, for example H₃PO₄

Polyprotic → Release many protons, for example EDTA

it is a weak acid.

In the first equilibrum, it release proton, and the second is released in the second equilibrium. So the first equilibrium will have a Ka1

H₂A  +  H₂O  ⇄  H₃O⁺  +  HA⁻                Ka₁

HA⁻  +  H₂O  ⇄  H₃O⁺  +  A⁻²               Ka₂

The HA⁻ will work as an amphoterous because, it can be a base or an acid, according to this:

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Answer:

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Explanation:

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12) In positron emission, a proton is transformed into a neutron. The mass number of the daughter nucleus is the same as its parent but the atomic number decreases by 1.

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