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zepelin [54]
3 years ago
12

Can someone please comfort me because i feel like i am going to cry and now i am crying so much right now, maybe i should cut ag

ain because now i am very depressed and stopped smiling and stopped caring about things like hurting myself.
Chemistry
2 answers:
Elan Coil [88]3 years ago
4 0

Answer:

hey no need for that lexi is back were is me punkin i need him to hold a me

Explanation:

E T PHONE HOME

olya-2409 [2.1K]3 years ago
3 0
Please dont harm yourself. whatever youre going through, you will get through it. i wish i could give you hug. you deserve so much happiness. but please dont hurt yourself.
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Which of the following is the best choice for presenting the percent
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3 years ago
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Write the net ionic equation for the reaction between hydrocyanic acid and potassium hydroxide. Do not include states such as (a
eimsori [14]

Answer:

The net ionic equation is as follows:

HCN(aq) + OH-(aq) ----> H20(l) + CN-(aq)

Explanation:

The reaction between Hydrocyanic acid, HCN, and sodium hydroxide is a neutralization reaction between a weak acid and a strong base.

Hydrocyanic acid being a weak acid ionizes only slightly, while sodium hydroxide being a strong base ionizes completely. The equation for the reaction is given below:

A. HCN(aq) + NaOH-(aq) ----> NaCN(aq) + H2O(l)

Since Hydrocyanic acid is written in the aqueous form as it ionizes only slightly and the ionic equation is given below:

HCN(aq) + Na+(aq)+OH-(aq) ----> Na+(aq)+CN-(aq) + H2O(l)

Na+ being a spectator ion is removed from the net ionic equation given below:

HCN(aq) + OH-(aq) ----> H20(l) + CN-(aq)

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3 years ago
In the equilibrium and concentration gizmo, you learned that you can predict the direction of a reaction by comparing the reacti
max2010maxim [7]

And the significant amount of volume can be differed by its solitude

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3 years ago
What two elements are commonly found in Mica, Quartz and Feldspar? Explain your answer.
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6 0
3 years ago
How would you prepare 500 mL of 0.360 M solution of CaCl2 from<br> solid CaCl2?
LenKa [72]

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

0.500 L \times \frac{0.360mol}{L} = 0.180 mol

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

0.180 mol \times \frac{110.98g}{mol} = 20.0 g

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

You can learn more about solutions here: brainly.com/question/2412491

4 0
2 years ago
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