1.turn the revolving turret so that low power lens come into position
2 place the microscope slide on the stage
3 look at the objective lens and the stage from the side as you turn adjust knob so that stage can move upward
4 look through the eyepiece and move the focus knob until image come into focus
5.adjust the condenser to regulate thee amount of light
6 move the microscope slide around until the sample is in the center of field of view
Option A: Electrons flow from nickel fork to silver rod, which is a cathode.
In a cell, an electrode with lower standard reduction potential will undergo oxidation and act as an anode and the one with higher standard reduction potential will undergo reduction and act as a cathode. The movement of electrons always takes place from anode to cathode.
In the given cell, silver rod and nickel fork are taken as metal electrodes. The reduction half reaction of silver and nickel are as follows:
Here, the standard electrode reduction potential of silver and nickel is 0.80 V and -0.26 V. Since, the electrode potential of silver is more than that of nickel thus, silver rod will undergo reduction and it will be cathode. Nickel fork will be anode as it undergoes oxidation.
Since, electrons flow from anode to cathode thus, it flows from Ni electrode to Ag electrode.
It satisfies the statement A, electrons flow from nickel fork to silver rod, which is a cathode. Therefore, correct option is A.
Answer:
Rate = -1/2 Δ[SO<sub>2</sub>]/Δt
so its gonna be (in more simple terms) rate= -1/2Δ(SO2)/Δt
Explanation:
a) Mass of gasiline = 18.9 kg; b) distance travelled = 204 mi
a) <em>Mass of gasoline
</em>
<em>Step 1</em>. Convert <em>$CDN to $US</em>
$US = $30.00 CDN × (0.942$US/$1 CDN) = $28.26 US
<em>Step 2</em>. Calculate the <em>volume of gasoline
</em>
V = $28.26 US × (1 gal gasoline/$3.82 US) = 7.399 gal
<em>Step 3</em>. Convert <em>gallons to litres
</em>
V =7.399 gal × (3.785 L/1 gal) = 28.00 L
<em>Step 4</em>. Calculate the <em>mass of the gasoline
</em>
Mass = 28 000 mL × (0.674 g/1 mL) = 18 900 g = 18.9 kg
<em>
b) Distance travelled
</em>
<em>Step 1</em>. Calculate the <em>kilometres</em>
Kilometres = 28.00 L × (100 km/8.53 L) = 328.3 km
<em>Step 2</em>. Convert <em>kilometres to miles</em>
Miles = 328.3 km × (1 mi/1.609 km) = <em>204 mi</em>
The average atomic mass of the element = 35.5
calculation
average atomic mass = sum of the masses of its isotope each multiplied by its natural abundance.
that is
[(75 x35) +(25 x37)] /100 = 35.5