Assuming that the number of mols are constant for both conditions:

Now you plug in the given values. V_1 is the unknown.

Separate V_1

V= 162.782608696 L
There are 2 sig figs
V= 160 L
The balanced chemical reaction is written as:
<span>2Al2O3 = 4Al + 3O2
We are given the amount of aluminum oxide used in the reaction. This will be the starting point for the calculations. We do as follows:
26.5 mol Al2O3 ( 3 mol O2 / 2 mol Al2O3 ) = 39.75 mol O2 produced</span>
Explanation:
When iodine heptafluoride reacts rapidly with water to give a mixture of periodic acid and hydrofluoric acid. Reaction equation for the same is as follows.

As it is given that there are
moles of iodine heptafluoride are present. Molar mass of
is 259.9 g/mol. Molar mass of
is 227.94 g/mol and molar mass of HF is 20.01 g/mol.
Now, according to the reaction equation
M
gives
M
.
Also, the volume is given as 795 ml or 0.795 L (as 1 mL = 0.001 L).
Hence, calculate the concentration of
into the solution as follows.
Concentration = 
= 
=
mol/L
or, = 0.047 M
Now, as 1 mol of
produces 7 mol HF. So,
M HF.
Therefore, concentration of HF will be calculated as follows.
Concentration of HF = 
= 0.33 M
Thus, we can conclude that concentration of periodic acid is 0.047 M and concentration of hydrofluoric acid is 0.33 M.