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allochka39001 [22]
4 years ago
14

How is gas different from a liquid

Chemistry
2 answers:
vlada-n [284]4 years ago
6 0
The gas is different from a liquid because the gas can escape a liquid doesn't
satela [25.4K]4 years ago
4 0
The atoms and molecules in gases<span> are much more spread out than in solids or</span>liquids<span>. They vibrate and move freely at high speeds. A </span>gas<span> will fill any container, but if the container is not sealed, the </span>gas<span> will escape. </span>Gas<span> can be compressed much more easily than a </span>liquid<span> or solid</span>
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tiny-mole [99]

d) protons and electrons.

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2 years ago
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i have an unknown volume of gas at a pressure of 0.50 atm a temperature of 325 k. If i raise the pressure to 1.2 atm, decrease t
Ronch [10]
Assuming that the number of mols are constant for both conditions:
\frac{P_1V_1}{T_1} =  \frac{P_2V_2}{T_2}
Now you plug in the given values. V_1 is the unknown. 
\frac{0.50 atm*V_1}{325K} = \frac{1.2 atm* 48 L}{230K}&#10;
Separate V_1
V_1= \frac{1.2 atm* 48 L * 325K }{230K*0.50 atm }
V= 162.782608696 L 

There are 2 sig figs

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3 0
3 years ago
How many moles of oxygen are produced when 26.5 mol of aluminum oxide are decomposed?
spayn [35]
The balanced chemical reaction is written as:

<span>2Al2O3 = 4Al + 3O2

We are given the amount of aluminum oxide used in the reaction. This will be the starting point for the calculations. We do as follows:

26.5 mol Al2O3 ( 3 mol O2 / 2 mol Al2O3 ) = 39.75 mol O2 produced</span>
7 0
3 years ago
Why are pennies good for simulating radioactive atoms? Check all that apply
gavmur [86]

Answer:

all of them are correct.

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5 0
3 years ago
The densevapor iodinee heptafluoride reacts rapidly with water to give a mixture of periodic acid and hydrofluoric acid .
erma4kov [3.2K]

Explanation:

When iodine heptafluoride reacts rapidly with water to give a mixture of periodic acid and hydrofluoric acid. Reaction equation for the same is as follows.

       IF_{7} + 6H_{2}O \rightarrow H_{5}IO_{6} + 7HF

As it is given that there are 3.72 \times 10^{-2} moles of iodine heptafluoride are present. Molar mass of IF_{7} is 259.9 g/mol. Molar mass of HIO_{4} is 227.94 g/mol and molar mass of HF is 20.01 g/mol.

Now, according to the reaction equation 3.72 \times 10^{-2} M IF_{7} gives 3.72 \times 10^{-2} M H_{5}IO_{6}.

Also, the volume is given as 795 ml or 0.795 L (as 1 mL = 0.001 L).

Hence, calculate the concentration of H_{5}IO_{6} into the solution as follows.

              Concentration = \frac{\text{no. of moles}}{volume}

                                      = \frac{3.72 \times 10^{-2}}{0.795 L}

                                      = 4.7 \times 10^{-2} mol/L

or,                                   = 0.047 M

Now, as 1 mol of IF_{7} produces 7 mol HF. So, 7 \times 3.72 \times 10^{-2} = 26.04 \times 10^{-2} M HF.

Therefore, concentration of HF will be calculated as follows.

             Concentration of HF = \frac{0.2604}{0.795}

                                              = 0.33 M

Thus, we can conclude that concentration of periodic acid is 0.047 M and concentration of hydrofluoric acid is 0.33 M.    

8 0
3 years ago
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