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1 year ago

Which of the following is not conserved in a chemical reaction?

2 answers:

6 0

Mass is not conserved in chemical reactions. Mass is therefore never conserved because a little of it turns into energy in every reaction

alukav5142 [94]1 year ago

6 0

Answer: D

Number of molecules wouldn’t change neither would atoms. Number of grams doesn’t really make since and I don’t think it changes so D

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Express the frequency in inverse seconds. n=5-->n=1

Natalija [7]

The frequencies expressed in inverse seconds are 5 s⁻¹ and 1 s⁻¹.

<h3>What is frequency?</h3>

Frequency is the number of complete cycles in a second made by a wave.

F = 1/T

F = n/t

F = 5/s = 5 s⁻¹ = 5Hz

F = 1/s = 1 s⁻¹ = 1Hz

Learn more about frequency here: brainly.com/question/254161

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1 year ago

The energy of moving atoms is

balandron [24]

The answer is Thermal Energy :)

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2 years ago

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How do H3O+ and OH relate to acids, bases and the pH scale?

Liula [17]

Answer: An acid is defined with having more [H₃O+] ions, and a base is defined with having more [OH-] ions. On the pH scale, an acid has a lower pH and a base has a higher pH. With this being said, the lower the pH, the more [H₃O+] ions are present and the higher the pH, the more [OH-] ions are present.

Explanation:

I hope this helps!! Pls give brainliest!! :)

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1 year ago

The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.

enot [183]

Answer:

$\large \boxed{\text{21.6 L}}$

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 180.16

C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g: 24.5

(a) Moles of C₆H₁₂O₆

$\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}$

(b) Moles of CO₂

$\text{Moles of CO}_{2} =\text{0.1360 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol CO}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.8159 mol CO}_{2}$

(c) Volume of CO₂

We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.960 atm

n = 0.8159 mol

T = 37 °C

(i) Convert the temperature to kelvins

T = (37 + 273.15) K= 310.15 K

(ii) Calculate the volume

$\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}$

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2 years ago

Can someone help me with this

Alexxx [7]

Answer:

uyfuj yfyuc

Explanation:

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2 years ago