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Ostrovityanka [42]
2 years ago
6

A 4.0 kg mass has a velocity of 10 m/s to the EAST. The 4.0 kg mass is subjected to a constant net force of 16 N to the WEST for

3.0 sec. What is the velocity of the 4.0 kg mass at the end of the 3.0 sec interval?​
Physics
1 answer:
julia-pushkina [17]2 years ago
5 0

Answer:

v = 2.0 m/s West

Explanation:

Let East be the positive direction

The initial momentum of the mass is p = mv = 4.0(10) = 40 kg•m/s East

This is acted on by an impulse of p = Ft = 16(3.0) = 48 N•s west

An impulse will result in a change of momentum

so final momentum of the mass is

40 - 48 = -8 kg•m/s or 8 kg•m/s West

-8 = 4.0v

v = -2.0 m/s or 2.0 m/s West

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Answer:

Explanation:

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Angular deceleration α = 2.23 rad / s

ω² = ω₀² -  2 α θ

0 = 15.8² - 2 x 2.23 θ

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Find the time t2 that it would take the charge of the capacitor to reach 99.99% of its maximum value given that r=12.0ω and c=50
defon

Answer:

Explanation:

Given that, .

R = 12 ohms

C = 500μf.

Time t =? When the charge reaches 99.99% of maximum

The charge on a RC circuit is given as

A discharging circuit

Q = Qo•exp(-t/RC)

Where RC is the time constant

τ = RC = 12 × 500 ×10^-6

τ = 0.006 sec

The maximum charge is Qo,

Therefore Q = 99.99% of Qo

Then, Q = 99.99/100 × Qo

Q = 0.9999Qo

So, substituting this into the equation above

Q = Qo•exp(-t/RC)

0.9999Qo = Qo•exp(-t / 0.006)

Divide both side by Qo

0.9999 = exp(-t / 0.006)

Take In of both sodes

In(0.9999) = In(exp(-t / 0.006))

-1 × 10^-4 = -t / 0.006

t = -1 × 10^-4 × - 0.006

t = 6 × 10^-7 second

So it will take 6 × 10^-7 a for charge to reached 99.99% of it's maximum charge

8 0
3 years ago
A geologist is comparing the properties of different minerals. He rubs each one on a piece of white tile and observes the color
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He performed a streak test, in which a piece of the mineral is rubbed across a piece of unglazed porcelain in order to determine the color of the mineral in powdered form.

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An 80.0-kg object is falling and experiences a drag force due to air resistance. The magnitude of this drag force depends on its
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Answer:

 Terminal velocity of object = 12.58 m/s

Explanation:

 We know that the terminal velocity is attained when drag force and gravitational force are of the same magnitude.

Gravitational force = mg = 80 * 9.8 = 784 N

Drag force = 12.0v+4.00v^2

Equating both, we have

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 So terminal velocity of object = 12.58 m/s    

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3 years ago
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