Question

A 4.0 kg mass has a velocity of 10 m/s to the EAST. The 4.0 kg mass is subjected to a constant net force of 16 N to the WEST for 3.0 sec. What is the velocity of the 4.0 kg mass at the end of the 3.0 sec interval?​

Answer 1

Answer:

v = 2.0 m/s West

Explanation:

Let East be the positive direction

The initial momentum of the mass is p = mv = 4.0(10) = 40 kg•m/s East

This is acted on by an impulse of p = Ft = 16(3.0) = 48 N•s west

An impulse will result in a change of momentum

so final momentum of the mass is

40 - 48 = -8 kg•m/s or 8 kg•m/s West

-8 = 4.0v

v = -2.0 m/s or 2.0 m/s West