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Ostrovityanka [42]
3 years ago
6

A 4.0 kg mass has a velocity of 10 m/s to the EAST. The 4.0 kg mass is subjected to a constant net force of 16 N to the WEST for

3.0 sec. What is the velocity of the 4.0 kg mass at the end of the 3.0 sec interval?​
Physics
1 answer:
julia-pushkina [17]3 years ago
5 0

Answer:

v = 2.0 m/s West

Explanation:

Let East be the positive direction

The initial momentum of the mass is p = mv = 4.0(10) = 40 kg•m/s East

This is acted on by an impulse of p = Ft = 16(3.0) = 48 N•s west

An impulse will result in a change of momentum

so final momentum of the mass is

40 - 48 = -8 kg•m/s or 8 kg•m/s West

-8 = 4.0v

v = -2.0 m/s or 2.0 m/s West

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Answer:

1.6 m/s

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Second, you need to find the total momentum of the system by adding the momentums of each sphere.

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Because momentum is conserved, this is equal to the momentum of the composite body.

Finally, to find the composite body's velocity, divide its total momentum by its mass. This is because mass*velocity=momentum

16/10=1.6

The velocity of the composite body is 1.6 m/s.

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2 years ago
if quasars often resemble little blue stars, what was it about them that so surprised astronomers when they were dis­covered?
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8 0
1 year ago
How much charge is on each plate of a 3.00-μF capacitor when it is connected toa 15.0-V battery? b) If this same capacitor is c
Sauron [17]

Answer:

(a) 45 micro coulomb

(b) 6 micro Coulomb

Explanation:

C = 3 micro Farad = 3 x 10^-6 Farad

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where, q be the charge.

q = 3 x 10^-6 x 15 = 45 x 10^-6 C = 45 micro coulomb

(b)

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q = C x V

where, q be the charge.

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3 years ago
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borishaifa [10]

Answer:

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3 years ago
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