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Llana [10]
3 years ago
15

. Using improved chemistry equipment in the late 1700s, chemists

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
8 0

Answer:vC

Explanation:

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What is the acceleration of an object that goes from 3 m/s to 5 m/s in 8 s?
nikdorinn [45]

Answer: 0.25m/s2

Explanation:

Acceleration is change in velocity with time

V = final velocity = 5m/s

U =Initial velocity = 3m/s

t = time = 8s

a = Acceleration =?

a = V — U / t

a = (5 — 3) / 8

a = 2/8

a = 0.25m/s2

8 0
3 years ago
Read 2 more answers
Calcium ions are removed from the sarcoplasm of the cardiac cell by the action of the sarcoplasmic reticulum (SR) Ca2+-ATPase pu
Ivan

Answer:

Sodium-calcium exchanger on the sarcolemma

Explanation:

The sodium-calcium exchanger which is an antiporter membrane protein, removes calcium from cells. The energy of the electrochemical gradient of sodium is used by allowing it to flow down its gradient while moving across the plasma membrane

7 0
3 years ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction:P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°
miskamm [114]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1835 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)    \Delta H_1=157kJ   ( × 4)

(2) P_4(g)+6Cl_2(g)\rightarrow 4PCl_3(g)     \Delta H_2=-1207kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[4\times (-\Delta H_1)]+[1\times \Delta H_2]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(4\times (-157))+(1\times (-1207))=-1835kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1835 kJ.

6 0
3 years ago
20 points I will give you brainliest if you answer in 5 mins
snow_lady [41]

Answer:Light bounces off of the mirror and then appears to come from behind the mirror.

Explanation:Plane mirrors form images that are virtual, upright and the same size and shape as the object it is reflecting.

When rays of light from the object hits a plane mirror they bounces off the mirror,that is they undergo reflection, and appear to originate from behind the mirror, resulting to the formation of a virtual image.

The image formed appears to be behind the plane in which the mirror lies. A virtual image is an image that is formed at a location from which the rays of light appear to come from. The image can not be formed on a screen..

4 0
3 years ago
Ca(C2H302)2<br> Name the following compounds.
lesya [120]

Answer:

nut

Explanation:

7 0
3 years ago
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