. Using improved chemistry equipment in the late 1700s, chemists
1 answer:
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Answer:
- <u>68.3g</u>
Explanation:
<u>1. Word equation:</u>
- <em>mercury(II) oxide → mercury + oxygen </em>
<u>2. Balanced molecular equation:</u>
- 2HgO → 2Hg + O₂(g)
<u>3. Mole ratio</u>
Write the ratio of the coefficients of the substances that are object of the problem:
<u>4. Calculate the number of moles of O₂(g)</u>
Use the equation for ideal gases:
<u>5. Calculate the number of moles of HgO</u>
<u>6. Convert to mass</u>
- mass = # moles × molar mass
- molar mass of HgO: 216.591g/mol
- mass = 0.315mol × 216.591g/mol = 68.3g
Answer:
77,007 Pa
Explanation:
Hello!
In this case, since the equivalence statement for atmospheres and pascals is:
1 atm = 101,325 Pa
We can set up the following conversion factor to obtain the pressure in pascals:
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