Answer:
I_FWHW = 3.2 μW / m²
Explanation:
In the analysis of optics and electricity a very useful magnitude is the width at half height (FWHW) and the intensity at this height, which is given by
I_FWHW = I₀ / 2
corresponds to the width of the line for this intensity.
In this case they give the maximum intensity for which
I_FWHW = 6.2 / 2
I_FWHW = 3.2 μW / m²
You do not give more data in your exercise, but the most interesting calculation is to find the angle values for which you have this intensity since it is this range is 50% of the energy of the system, have I write the equation for this calculation
I = Io cos² x₁ (sin x / x)²
x₁ = π d sin θ /λ
x = π b sin θ /λ
where d is the separation of the slits and b the width of each slit
<h2>The symbol is called an Alpha and means <em><u>"varies as"</u></em></h2>
At 1.70 atm, a gas sample occupies 4.25 liters. If the pressure in the gas increases to 2.40 atm, what will the new volume be?
Answer:
3.01L
Explanation:
Given parameters:
Initial pressure, P1 = 1.7atm
Initial volume, V1 = 4.25L
Final pressure, P2 = 2.4atm
Unknown:
Final or new volume, V2 = ?
Solution:
To solve this problem, we use Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes, if the temperature is constant".
P1 V1 = P2 V2
P1 is the initial pressure
V1 is the initial volume
P2 final pressure
V2 final volume
1.7 x 4.25 = 2.4 x V2
V2 = 3.01L
That is not a question but not all scientific theories have stood the test of time
