Answer:
The answer is hydrogen and oxygen
Explanation:
<span>The trajectory (parabola) for a "particle" of water follows from:
h(t) = v(0) sin(angle) t - 1/2 g t^2
x(t) = v(0) cos(angle) t
From the second equation t = x / (v(0) cos(angle) )
and substitution in the first to eliminate t gives the parabola h(x):
h(x) = x tan(angle) - (g/(2v(0)^2 cos(angle)^2) x^2
h(x) = 0 is solved by x=0 (where the trajectory starts) and at
x = 2 v(0)^2 tan(angle) cos^2(angle) / g
x = 2 v(0)^2 sin(angle) cos(angle) / g
x = v(0)^2 sin(2 angle) / g [[ using sin(2 ) = 2 sin(s) cos(s) ]]
For the first question (the 2.0m distance question) you have therefore to solve for angle the equation
2.0= 2*(6.5)^2 sin(2 angle) / 9.81
sin(2 angle) = 0.23
angle = 1/2 * arcsin(0.23) = 6.65 degrees
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
Answer:
317.22
Explanation:
Given
Circular platform rotates ccw 93.1kg, radius 1.93 m, 0.945 rad/s
You 69.7kg, cw 1.01m/s, at r
Poodle 20.2 kg, cw 1.01/2 m/s, at r/2
Mutt 17.7 kg, 3r/4
You
Relative
ω = v/r
= 1.01/1.93
= 0.522
Actual
ω = 0.945 - 0.522
= 0.42
I = mr^2
= 69.7*1.93^2
= 259.6
L = Iω
= 259.6*0.42
= 109.4
Poodle
Relative
ω = (1.01/2)/(1.93/2)
= 0.5233
Actual
ω = 0.945- 0.5233
= 0.4217
I = m(r/2)^2
= 20.2*(1.93/2)^2
= 18.81
L = Iω
= 18.81*0.4217
= 7.93
Mutt
Actual
ω = 0.945
I = m(3r/4)^2
= 17.7(3*1.93/4)^2
= 37.08
L = Iω
= 37.08*0.945
= 35.04
Disk
I = mr^2/2
= 93.1(1.93)^2/2
= 173.39
L = Iω
= 173.39*0.945
= 163.85
Total
L = 109.4+ 7.93+ 36.04+ 163.85
= 317.22 kg m^2/s