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3 years ago

Two elements that have the same ground-state valence shell configuration of ns 2 np 2 are

Chemistry

1 answer:

kvv77 [185]3 years ago

6 0

Answer:

carbon and silicon

Explanation:

Various groups of elements in the periodic table have different outermost shell electron configurations. Actually, elements are classified into groups on the basis of the number of electrons on the outermost shell of those elements. All elements with the same number of electrons on their outermost shell belong to the same group in the periodic table.

For elements in group 14, they all have four electrons on their outermost shell. Their general outer electron configuration is ns2 np2 as shown in the question. Two prominent members of this group are carbon and silicon. This ns2 np2 is the ground state outer electron configuration of all group 14 elements in the periodic table.

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Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p

Butoxors [25]

Answer:

$3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

$BiO_3^-\rightarrow Bi^{3+}$

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

$(Bi^{5+}O_3)^-\rightarrow Bi^{3+}$

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

$6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O$

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

$6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Then, we accommodate the waters to obtain:

$3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Best regards!

7 0

3 years ago

An acid and a base react to form salt and water. Which of the following best describes this type of chemical reaction? Redox Neu

I am Lyosha [343]

Answer:

Neutralization

Explanation:

When an acid react with base it form the salt and water. The reaction is also called neutralization reaction because both neutralize each other.

In neutralization reaction equal amount of acid and base react to neutralize each other and equal amount of water and salt are formed. When pH does not reach to 7 its means there is less amount of one of reactant which is not fully neutralize.

Neutralization reactions are also used as first aid. For example when someone is dealing with HCl for cleaning purpose of toilet and get touched. It is advised to neutralize it with soap, milk or egg white.

Example:

Hydrochloric acid when react with the sodium hydroxide, a salt sodium chloride and water are formed.

Chemical equation:

HCl + NaOH → NaCl + H₂O

Titration:

Neutralization reactions are also used to determine the concentration of solution. Titration is a quantitative technique in which acid or base is gradually added into the solution whose concentration is to be determine until the neutral point is reached.

3 0

3 years ago

Read 2 more answers

Newton believed _______ _______ were encoded alchemic recipes.

Zinaida [17]

I would say "Greek myths"

8 0

3 years ago

Read 2 more answers

C2h4 3 o2 2 co2 2 h2o

Marat540 [252]

Use the question marck Moles of CO2
The the giving = 0.624 mol O2
Find the CF faction = 1 mole= 32.00 of O2

O= 2x16.00= 32.00amu ( writte this in the cf fraction)
SET UP THE CHART
Always start with the giving

0.624 mol O2 / 1mol of CO2
___________ / _____________ = Cancel the queal ( O2)
/ 32.00c O2
/
/
Multiply the top and divide by the bottom
0.624 mol CO x 1mol CO2 = 0.624 divide by 32.00 O2 =0.0195
You should look at the giving number ( how many num u gor ever there)
Ur answer should have the same # as ur givin so
= 0.0195
= .0195 mol of CO2

3 0

3 years ago

A mixture of krypton and argon gas is expanded from a volume of 88.0L to a volume of 100.0L, while the pressure is held constant

Firlakuza [10]

Answer:

-3.28 × 10⁴ J

Explanation:

Step 1: Given data

Pressure exerted (P): 27.0 atm

Initial volume (Vi): 88.0 L

Final volume (Vf): 100.0 L

Step 2: Calculate the work (w) done by the gaseous mixture

We will use the following expression.

w = -P × ΔV = -P × (Vf - Vi)

w = -27.0 atm × (100.0 L - 88.0 L)

w = -324 atm.L

Step 3: Convert w to Joule (SI unit)

We will use the conversion factor 1 atm.L = 101.325 J.

-324 atm.L × 101.325 J/1 atm.L = -3.28 × 10⁴ J

5 0

3 years ago