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tatiyna
3 years ago
5

Why does a liquid need a container and a solid doesn't?

Physics
1 answer:
mamaluj [8]3 years ago
7 0
It is mainly because a solid has a much stronger atom bonds compared to liquid
When liquid is poured, it will always tried to fill up its container because the weakness in its atom bond allow it to do so.
Meanwhile, the form of a solid will stay exactly the same no matter where we put it because the strength of their bond will retain their form.

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The acceleration due to gravity on the surface of Venus is 8.83 m/s2. An object with a mass of 5.23 kg has what weight on Venus?
Marat540 [252]
Weight = m times g = 5.23 times 8.83 = 46.18 N
6 0
3 years ago
Wyatt is moving a box with a mass of 37 kg a distance of 37 meters. Wyatt did 360 J of work in 2 minutes when moving the box. Wh
pentagon [3]
His power output was 3 Watt (360 Joule/120 seconds). The power output can be calculated by dividing the quantity of work by the amount of second needed for the activity and also by multiplying the force amount with the velocity of the activity. The power output usually used for measuring the ability of machine for doing its job.
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Identify the law, write the equation and calculate the answer to the problem below.
lyudmila [28]

Find refractive index first

\\ \rm\Rrightarrow \mu=\dfrac{c}{v}

\\ \rm\Rrightarrow \mu=\dfrac{1.0003}{1.33}

\\ \rm\Rrightarrow \mu =0.75

Now

\\ \rm\Rrightarrow \dfrac{sini}{sinr}=\mu

\\ \rm\Rrightarrow \dfrac{sin45}{sinr}=0.75

\\ \rm\Rrightarrow \dfrac{sin45}{0.75}=sinr

\\ \rm\Rrightarrow sinr=0.94

\\ \rm\Rrightarrow r=sin^{-1}(0.94)

\\ \rm\Rrightarrow r=70^{\circ}

5 0
2 years ago
A net force, the magnitude of which is 3800 N, accelerates a 1260-kg vehicle for 10.0 s. The vehicle travels 50.0 m during this
Novay_Z [31]

Answer:

SEE EXPLANATION

Explanation:

p =  \frac{fd}{t}  \\ where \: \\p  = power \\  f = force \\ d = distance \\ and \: t = time \\  \\ p =  \frac{3800 \times 50}{10}  \\ p =  \frac{190000}{10}  \\ p = 19000w

7 0
3 years ago
A tiger leaps horizontally out of a tree that is 6.00 m high. If he lands 2.00 m from the base of the tree, calculate his initia
Musya8 [376]

Answer:

The initial speed of the tiger is 1.80 m/s

Explanation:

Hi there!

The equation of the position vector of the tiger is the following:

r = (x0 + v0 · t, y0 + 1/2 · g · t²)

Where:

r = position vector at a time t.

x0 = initial horizontal position.

v0 = initial horizontal velocity.

t = time.

y0 = initial vertical position,

g = acceleration due to gravity.

Let´s place the origin of the frame of reference on the ground at the point where the tree is located so that the initial position vector will be:

r0 = (0.00, 6.00) m

We can use the equation of the vertical component of the position vector to obtain the time it takes the tiger to reach the ground.

y = y0 + 1/2 · g · t²

When the tiger reaches the ground, y = 0:

0 = 6.00 m - 1/2 · 9.81 m/s² · t²

2 · (-6.00 m) / -9.81 m/s² = t²

t = 1.11 s

We know that in 1.11 s the tiger travels 2.00 m in the horizontal direction. Then, using the equation of the horizontal component of the position vector we can find the initial speed:

x = x0 + v0 · t

At t = 1.11 s, x = 2.00 m

x0 = 0

2.00 m = v0 · 1.11 s

2.00 m / 1.11 s = v0

v0 = 1.80 m/s

The initial speed of the tiger is 1.80 m/s

4 0
3 years ago
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