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3 years ago

Which of the following best approximates the value g(h(1))? A.-7 B.-5 C.0 D.2

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

6 0

Answer:

Option (B)

Step-by-step explanation:

From the graph attached,

There are two functions graphed,

y = f(x) and y = h(x)

h(1) = 0 [Output value of function 'h' at the input value x = 1]

Since, g[h(1)] = g(0)

Therefore, value of function 'h' (output value) at (input value) x = 0,

g(0) = -5

Option B will be the correct option.

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Jack brought a keyboard priced at $183.60 the sales tax was found by multiplying the price of the keyboard by 0.05 what was the

blondinia [14]

Answer:

192.78‬

Step-by-step explanation:

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3 years ago

Y"-4y'+4y=0 y1=e^2x find the general solution

Karo-lina-s [1.5K]

Given that $y_1=e^{2x}$ is a known solution to the ODE, we can reduce the order of the ODE to find a second solution of the form

$y_2=y_1v=e^{2x}v$
$\implies {y_2}'=2e^{2x}v+e^{2x}v'$
$\implies {y_2}''=4e^{2x}v+4e^{2x}v'+e^{2x}v''$

Substituting into the ODE, we get

$(e^{2x}v''+4e^{2x}v'+4e^{2x}v)-4(e^{2x}v'+2e^{2x}v)+4e^{2x}v=e^{2x}$
$e^{2x}v''=e^{2x}$
$v''=1$
$\implies v'=C_1$
$\implies v=C_1x+C_2$
$\implies y_2=C_1xe^{2x}+C_2e^{2x}$

We already know about $e^{2x}$ as a solution to the ODE, which means $y_2=xe^{2x}$ .

That covers the characteristic solution. To find the particular solution to the nonhomogeneous ODE, suppose there is a solution of the form

$y_p=ax^2e^{2x}$
${y_p}'=2ax(x+1)e^{2x}$
${y_p}''=2a(2x^2+4x+1)e^{2x}$

Substituting into the ODE yields

${y_p}''-4{y_p}'+4{y_p}=2ae^{2x}=e^{2x}\implies a=\dfrac12$

so that the general solution is

$y=C_1y_1+C_2y_2+y_p$
$y=C_1e^{2x}+C_2xe^{2x}+\dfrac12x^2e^{2x}$

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3 years ago

How can you apply the remainder theorom

Goshia [24]

In remainder theorem, first we set the given factor or the divisor to 0 and solve for the variable. Then we put the value of the vriable that we got on setting the divisor to 0, in the given polynomial and check the result . If the result is 0, then the given divisor is a factor, else it is not. For e.g. Suppose we have to see whether x-1 is a factor of x square -2x+1 or not. So we set x-1to 0 that is x-1=0 which gives x=1 . Now we put 1 for x in x square -2x+1 that is 1-2+1 =0, so x-1 is a factor of the given polynomial .

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3 years ago

ANSWER ASAP PLEASE!! CORRECT ANSWER WILL GET BRAINLIEST!

slava [35]

Answer:

Step-by-step explanation:

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3 years ago

One side of a regular hexagon is 18 cm. which is the perimeter

zhenek [66]

"Hexagon" means it has six sides.
"Regular" means all of its sides are the same length.

So the perimeter of a regular hexagon is (6) times (the length of any side).

6 x 18 cm = <em>108 cm</em>

8 0

3 years ago

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