Answer:

Explanation:
Hello,
In this case, since the acid is monoprotic, we can notice a 1:1 molar ratio between, therefore, for the titration at the equivalence point, we have:

Thus, solving for the moles of the acid, we obtain:

Then, by using the mass of the acid, we compute its molar mass:

Regards.
Answer:
Robert Boyle
Explanation:
En muchos textos se suele considerar a Robert Boyle como el científico que introdujo en la Química un concepto de elemento diferente al empleado por los aristotélicos o por los alquimistas y que sirvió de antecedente al que formulara Lavoisier en 1789.
Answer:
draw the carbon chain is containing 6 carbon then attach the aldehyde group with edge carbon in chain then put the put double bond at 3 no. carbon
Answer:
165.5 g of CO2
Explanation:
We must first put down the balanced reaction equation:
C4H10(g) + 13/2 O2(g) ------> 4CO2(g) + 5H2O(g)
From the reaction equation, one mole of butane occupies 22.4 L hence we can establish the stoichiometry of the reaction thus:
22.4 L of butane created 174 g of CO2
Therefore 21.3 L of butane will create 21.3 × 174/22.4 = 165.5 g of CO2