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Ivenika [448]
3 years ago
13

Common additives to drinking water include elemental chlorine, chloride ions, and phosphate ions. Recently, reports of elevated

lead levels in drinking water have been reported in cities with pipes that contain lead, Pb(s). When Cl2(aq) flows through a metal pipe containing Pb(s), some of the lead atoms oxidize, losing two electrons each, and aqueous chloride ions form. (a) Write a balanced, net-ionic equation for the reaction between Pb(s) , and Cl2(aq).
Chemistry
1 answer:
posledela3 years ago
8 0

Answer:

See explaination

Explanation:

Balanced net ionic reaction.

Pb(s) + Cl2(g) ----- Pb2+ + 2Cl-

oxidation reaction :Pb(s) --- Pb2+ + 2e-

Reduction reaction:Cl2 + 2e- -----Cl-

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A typical aspirin tablet contains 327 mg of acetylsalicylic acid, HC9H7O4. Calculate the pH of a solution that is prepared by di
yawa3891 [41]

Answer:

2.8

Explanation:

First, we will calculate the molarity of the acetylsalicylic acid solution.

M = mass of solute (g) / molar mass of solute × volume of solution (L)

M = 0.327 g / 180.158 g/mol × 0.237 L

M = 7.66 × 10⁻³ M

For a weak acid such as acetylsalicylic acid, we can find the concentration of H⁺ using the following expression.

[H⁺] = √(Ca × Ka)

where,

Ca: concentration of the acid

Ka: acid dissociation constant

[H⁺] = √(7.66 × 10⁻³ × 3.3 × 10⁻⁴)

[H⁺] = 1.6 × 10⁻³ M

The pH is:

pH = -log [H⁺]

pH = -log 1.6 × 10⁻³ = 2.8

6 0
3 years ago
What is the pH of a solution after the addition of 30.0 mL of 0.100 M NaOH to 50.0 mL of 0.10 M HBr?
Pani-rosa [81]

Answer:

pH = 1.6

Explanation:

  • HBr + NaOH ⇒ NaBr + H2O

0 mL NaOH:

  • HBr ↔ H3O+  +  Br-

⇒ [ H3O+] = M HBr = 0.1 M

⇒pH = -log [H3O+] = 1

30 mL NaOH:

⇒ mol NaOH = 0.1 mol / L * 0.03 L =  3 E-3 mol

⇒ mol HBr = 0.05 L * 0.1 mol/L = 5 E-3 mol

⇒ M HBr = ( 5 E-3 mol - 3 E-3 mol) / 0.08 L = 0.025 M

⇒ pH = - log (0.025) = 1.6

7 0
3 years ago
A 25.0 g sample of an alloy was heated to 100.0 oC and dropped into a beaker containing 90 grams of water at 25.32 oC. The tempe
elena55 [62]

Answer:

The specific heat of the alloy C_{a} = 0.37 \frac{KJ}{Kg K}

Explanation:

Mass of an alloy m_{a} = 25 gm

Initial temperature T_{a} = 100°c = 373 K

Mass of water m_{w} = 90 gm

Initial temperature of water T_{w} = 25.32 °c = 298.32 K

Final temperature T_{f} = 27.18 °c = 300.18 K

From energy balance equation

Heat lost by alloy = Heat gain by water

m_{a} C_{a}  [T_{a} - T_{f}] = m_{w} C_w (T_{f} -T_{w} )

25 × C_{a} × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)

C_{a} = 0.37 \frac{KJ}{Kg K}

This is the specific heat of the alloy.

4 0
4 years ago
Describe the whole process of Aluminum extraction from bauxite.​
AlekseyPX

Answer:

Extraction of aluminium

Aluminium ore is called bauxite . The bauxite is purified to produce aluminium oxide, a white powder from which aluminium can be extracted. The extraction is done by electrolysis. The ions in the aluminium oxide must be free to move so that electricity can pass through it.

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3 years ago
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What is the structure of beeswax that contains 16 carbon of carboxylic acid and 30 carbon of alcohol?
melisa1 [442]
This is the answer hope this helps

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4 years ago
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