Answer:
Horizontal force is 16.97 N.
Explanation:
It is given that,
Mass of the block, m = 2 kg
It is on an incline at a 60 degree angle is held in equilibrium by a horizontal force. We need to find the magnitude of horizontal force. The force acting on the block is its weight mg.
The horizontal component of force is,
The vertical component of force is,
So, the horizontal component of force is,
So, the horizontal component of force is 16.97 N.
Answer:
The natural frequency will be 228.11 rad/sec
Explanation:
We have given Inductance L = 0.048 Henry
And the capacitance C = 0.0004 farad
We have to find natural frequency
When only inductor and capacitor is present in the circuit then it is known as LC circuit and Natural frequency of LC circuit is given by
So the natural frequency will be 228.21
Answer:
(a) 8 V, (b) 144000 V, (c) 2 x 10^(-8) C
Explanation:
(a) charge, q = 5 μC , Work, W = 40 x 10-^(-6) J
The electric potential is given by
W = q V
(b)
charge, q = 8 x 10^(-6) C, distance, r = 50 cm = 0.5 m
Let the potential is V.
(c)
Work, W = 8 x 10^(-5) J, Potential difference, V = 4000 V
Let the charge is q.
W= q V