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enyata [817]
3 years ago
12

What kind of changes cause iron to rust ?

Chemistry
1 answer:
loris [4]3 years ago
8 0

Answer:

ways it rust are

1.you put water on it

2.let it sit out side for about a month or 2

                       or

you put the iron in water still wait a month or 2 then

you got the full or sum rusty parts

Explanation:

ether way you need water, air ,and the main thing... IRON

You might be interested in
What type of reaction is: iron + lead nitrate -> lead +
Vladimir [108]

Answer:

C. single replacement

Explanation:

In a single replacement reaction, one atom replaces another.

The general form of a single replacement reaction is: A + Bc ⇒ Ac + B

A   +  B  ×  c      ⇒   B   +  A × c

↓       ↓      ↓            ↓       ↓    ↓

Fe +  Pb(NO₃)₂ ⇒  Pb  + Fe(NO₃)₂

Iron switched places with lead so the reaction is a single replacement reaction.

Hope this helps.

4 0
4 years ago
The pressure of a gas at constant temperature is increased by a factor od 4. By what factor does the volume change?
viktelen [127]

Answer:

A

Explanation:

The formula used is

PV = P1 * V1

P = x

P1 = 4x

V1 = 1

V2 = ?

x * 1 = 4x * V2          Divide both sides by x

x/x = 4x /x * V2

1 = 4*V2                   Divide by 4

1/4 = 4*V2/4

1/4 = V2

The answer is A

4 0
4 years ago
Pls help me if u can. tysm​
xenn [34]

Answer:

For question 1...... First exchange the valencies...

6 0
3 years ago
Need help fast plzzz!!! Please help.
IRINA_888 [86]

Answer:

1. 0.5333333m (Calculator Soup Work Calculator)

2.

9. 29.1666666667% efficient

10. 44.5% efficient

Explanation:

will do other answers later

5 0
3 years ago
Determine how many gmol, kmol, and lbmols there are in 50 kilograms of n-hexane.
Artist 52 [7]

Answer: 581 gmol

0.581 kmol

1.28\times 10^{-3}lbmol

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{50\times 1000g}{86g/mol}=581mol

1. The conversion for mol to gmol

1 mol = 1 gmol

581 mol= \frac{1}{1}\times 581=581gmol

2. The conversion for mol to kmol

1 mol = 0.001 kmol

581 mol= \frac{0.001}{1}\times 581=0.581kmol

3. The conversion for mol to lbmol

1 mol = 2.2\times 10^{-3}lbmol

581 mol= \frac{2.2\times 10^{-3}}{1}\times 581=1.28\times 10^{-3}lbmol

3 0
3 years ago
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