Hummm... Its not normally reported that way. First you need to determine how many miles you are getting per gallon. A good estimate is that you will discharge 19.6 pounds of CO2 from burning 1 gallon of gasoline. This does not depend on the power or configuration of the engine. Of course if the car gets more miles per gallon of gasoline, you will get less CO2 per unit of service rendered (that is, less CO2 per mile traveled).
<span>Once you determine how many miles per gallon you are getting then divide that by 19.6 and that should give you the pounds of Carbon dioxide produced per mile. </span>
<span>The U.S. Department of Energy and the U.S. Environmental Protection Agency recently launched a new Fuel Economy Web Site designed to help the public factor energy efficiency into their car buying decisions. This site offers information on the connection between fuel economy, advanced technology, and the environment. </span>
Answer:
Chronic stress, or a constant stress experienced over a prolonged period of time, can contribute to long-term problems for heart and blood vessels. The consistent and ongoing increase in heart rate, and the elevated levels of stress hormones and of blood pressure, can take a toll on the body.
Answer:
1 g
Explanation:
The following data were obtained from the question:
Original amount (N₀) = 32 g
Time (t) = 71.5 days
Half-life of phosphorus (t½) = 14.3 days
Amount remaining (N) =?
Next, we shall determine the rate of disintegration. This can be obtained as follow:
Half-life of phosphorus (t½) = 14.3 days
Decay constant (K) =?
K = 0.693 / t½
K = 0.693 / 14.3
K = 0.0485 /day
Finally, we shall determine the amount remaining as illustrated below:
Original amount (N₀) = 32 g
Time (t) = 71.5 days
Decay constant (K) = 0.0485 /day
Amount remaining (N) =?
Log (N₀/N) = Kt/2.303
Log (32/N) = 0.0485 × 71.5 / 2.303
Log (32/N) = 3.46775 / 2.303
Log (32/N) = 1.5058
Take the antilog of 1.5058
32/N = antilog (1.5058)
32/N = 32.05
Cross multiply
32 = N × 32.05
Divide both side by 32.05
N = 32 / 32.05
N = 0.998 ≈ 1 g
Thus, the amount remaining after 71.5 days is approximately 1 g.
Benzyl Amine is synthesized from Toluene in two steps;
Step 1: Bromination of Methyl Group in Toluene: Bromination is carried out on methyl group present on Benzene ring through free radical mechanism by treating toluene with <span>N-Bromosuccinimide (NBS) and Benzyl Bromide is formed.
Step 2: Benzyl Bromide into Benzyl Amine; This step is carried out utilizing a neme reaction "Gabriel Reaction". Benzyl bromide is treated with </span>Potassium Phthalamide and an intermediate is formed which on treatment with Hydrazine produces Benzyl amine.
