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3 years ago

Which of the following would have the largest amount of mass?

Chemistry

2 answers:

Elodia [21]3 years ago

7 0

Answer:

1 kg

Explanation:

prefix nano means 10^-9

kilo 10^3

mili 10^-3

centi 10^-2

the largest amount is 1 kg

dedylja [7]3 years ago

3 0

The correct answer is B. 1 kilogram (kg)

Explanation:

Mass refers to the amount of matter that can be found in an object or body, this property can be measured using different units such as grams, kilograms, decagrams, centigrams, etc. although each of this, measures different amounts of mass. In this way, the kilogram (kg) is the most common unit used for mass and the largest from the options presented, as a nanogram is equivalent to $10^{-12}$ kilograms, a milligram is equivalent to $10^{-6}$ kilograms and a centigram is equivalent to $10^{-5}$ kilograms, which means all nanograms, milligrams, and centigrams are smaller units than kilograms.

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A compound is made up of 28 g N, 24 g C, 48 g O, and 8 g H .What is the empirical formula?

vovikov84 [41]

Answer:

$\rm C_2H_8N_2O_3$ .

Explanation:

<h3>Step One: calculate the coefficients. </h3>

Look up the relative atomic mass of these four elements on a modern periodic table:

$\rm C$ : approximately $12$ .
$\rm H$ : approximately $1$ .
$\rm N$ : approximately $14$ .
$\rm O$ : approximately $16$ .

The relative atomic mass of an element is numerically equal to the mass (in grams, $\rm g$ ,) of one mole of atoms of this element.

For example, the relative atomic mass of $\rm C$ is approximately $12$ . Therefore, each mole of $\rm C\!$ atoms would have a mass of $12\; \rm g$ .

This sample contains $24\; \rm g$ of carbon. That would correspond to approximately $\displaystyle \left(\frac{24}{12}\right)\; \rm mol = 2\; \rm mol$ of $\rm C$ atoms.

Similarly, for the other three elements:

$\displaystyle n(\mathrm{H}) \approx \frac{8\; \rm g}{1\; \rm g \cdot mol^{-1}} = 8\; \rm mol$ .

$\displaystyle n(\mathrm{N}) \approx \frac{28\; \rm g}{14\; \rm g \cdot mol^{-1}} = 2\; \rm mol$ .

$\displaystyle n(\mathrm{O}) \approx \frac{48\; \rm g}{16\; \rm g \cdot mol^{-1}} = 3\; \rm mol$ .

Hence, the ratio between these elements in this compound would be:

$n(\mathrm{C}): n(\mathrm{H}): n(\mathrm{N}):n(\mathrm{O}) = 2: 8 : 2 : 3$ .

In the empirical formula of a compound, the coefficients should represent the smallest possible integer ratio between the number of atoms of these elements.

$n(\mathrm{C}): n(\mathrm{H}): n(\mathrm{N}):n(\mathrm{O}) = 2: 8 : 2 : 3$ is indeed the smallest possible integer ratio between the number of atoms of these elements.

<h3>Step Two: arrange the elements in an appropriate order</h3>

Apply the Hill System to arrange these four elements in the empirical formula. In the Hill System:

If carbon, $\rm C$ , is present in this compound, then:

$\rm C$ (carbon) and then $\rm H$ (hydrogen) will be the first two elements listed in the formula (ignore the hydrogen if it is not in the compound.)
The other elements in this compound will be listed in alphabetical order.

If there is no carbon $\rm C$ in this compound, then list all the elements in this compound in alphabetical order.

Both $\rm C$ (carbon) and $\rm H$ (hydrogen) are found in this compound. Therefore, the first element in the list would be $\rm C\!$ . The second would be $\rm H\!$ , followed by $\rm N\!$ and then $\rm O\!$ .

Hence, the empirical formula of this compound would be $\rm C_2H_8N_2O_3$ .

6 0

3 years ago

How many moles are represented by 3.01 - 1023 helium atoms?

Pavlova-9 [17]

Answer:

0.5 mol

Explanation:

Given data:

Number of atoms of He = 3.01 ×10²³

Number of moles = ?

Solution:

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.02 × 10²³ is called Avogadro number.

1 mole = 6.02 × 10²³ atoms

3.01 ×10²³ atoms × 1 mol / 6.02 × 10²³ atoms

0.5 mol

7 0

3 years ago

Three isotopes of carbon are indicated below: 12/6 C, 13/6 C, 14/6 C How are these isotopes alike?

Ugo [173]

They all share the same atomic number (number of protons)

7 0

3 years ago

The most common substance on earth is water. True Or False

shtirl [24]

True... water and land mostly covers up the earth... go anywhere and there is water...

4 0

3 years ago

the temperature of a sample of copper increased by 23.0 C when 265 J of heat was applied. What is the mass of the sample?

Anuta_ua [19.1K]

Answer: 29.93g

Explanation:

Q = 265J

C = 0.385J/g/°C

Δt = 23°C

M =?

Q = MCΔT

M = Q / CΔT = 265 / (0.385x23)

M = 29.93g

3 0

3 years ago