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Rudik [331]
3 years ago
7

Small-plane pilots regularly compete in "message drop" competitions, dropping heavy weights (for which air resistance can be ign

ored) from their low-flying planes and scoring points for having the weights land close to a target. A plane 55m above the ground is flying directly toward a target at 48m/s .A)At what distance from the target should the pilot drop the weight?Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
Arte-miy333 [17]3 years ago
4 0

Answer:

It should be dropped from 160.80m

Explanation:

To calculate the time it takes the weight to reach the ground from 55m we need to consider that the only acceleration applied to it is the gravity, the height at any time t can be calculate as:

Y=Y_{0}+Vy_{0}*t-1/2*g*t^{2}

If we consider that it starts from Y_{0}=55m to reach Y=0, and that the initial velocity on the vertical axis equals zero:

0=55m-1/2*g*t^{2}

solving for t:

t=\sqrt{\frac{55m*2}{g} } =\sqrt{\frac{110m}{9.8m/s^{2} } }=3.35s

Now to calculate the horizontal distance from the target:

X=X_{0}+Vx_{0}*t-1/2*a*t^{2}

We have to consider that:

It will travel from X_{0}=0m (we set the reference on the dropping point so the result X will be de needed distance;

As the air resistance can be ignored there is no force on the horizontal direction, a=0;

The starting velocity Vx_{0} is the same of the plane velocity

It will be traveling for a time t calculated before;

replacing this on the equation:

X=48m/s*3.35s=160.80m

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A hot air balloon is traveling vertically upward at a constant speed of 4.5 m/s. When it is 28 m above the ground, a package is
ella [17]

Answer:

1.97 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow 21=4.5t+\frac{1}{2}\times -9.8\times t^2\\\Rightarrow 21=-4.5t-4.9t^2\\\Rightarrow 4.9t^2+4.5t-28=0\\\Rightarrow 49t^2+45t-280=0

Solving the above equation we get

t=\frac{-45+\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}, \frac{-45-\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}\\\Rightarrow t=1.97, -2.89

So, the time the package was in the air is 1.97 seconds

3 0
3 years ago
Vivian went on a bicycle trip through Germany with her family. One afternoon, she rode her bicycle along a long flat road at a c
natima [27]

d = distance traveled by her on her bicycle on a long flat road = 24 kilometer

t = time taken by her to travel distance "d" on her bicycle on a long flat road = 1.2 hours

v = average speed of vivian = ?

we know that average speed is given as

v = d/t

inserting the values in the above formula

v = 24 kilometer / 1.2 hour

v = 20 kilometer/hour


hence the correct choice is

C) 20 km/h



8 0
3 years ago
????????????????????????
Kipish [7]

Answer:

Velocity

Explanation:

"The principle is that the slope of the line on a position-time graph is equal to the velocity of the object. If the object is moving with a velocity of +4 m/s, then the slope of the line will be +4 m/s."

^^This explanation is from physicsclassroom.com

3 0
3 years ago
3. A car has a mass of 2.50 x 10^3 kg. If the force acting on the car is 7.65 x 10^3 N to the
const2013 [10]

Answer:

3.06m/s² to the east

Explanation:

Given parameters:

Mass of car = 2.5 x 10³kg

Force acting on the car  = 7.65 x 10³N

Unknown:

Acceleration of the car  = ?

Solution:

From Newton's second law of motion:

      Force  = mass x acceleration

   Acceleration  = \frac{Force }{mass}   = \frac{7.65 x 10^{3} }{2.5 x 10^{3} }    = 3.06m/s² to the east

6 0
3 years ago
What happens to the particles of the liquid inside a thermometer when the thermometer is heated?
aev [14]
The particles of the liquid inside a thermometer speed up and spread apart when the thermometer is heated. In short, the particles expand from one another when they're heated, and become condensed and compact when chilled.

5 0
3 years ago
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