Answer:
The force on the proton will be twice in comparison with the force experienced by the electron.
Explanation:
The magnetic force acting on the moving charge particle is perpendicular to the velocity as well as the magnetic field. The factors upon which the magnitude of the force is depending and proportional are as follows:
1 Magnitude of the charge particle.
2 Magnitude of the velocity of moving charge.
3 Magnitude of magnetic field.
4 Sine of angle between the velocity and magnetic field.
As far as direction is concerned, it can be find out by right hand rule.
Lets consider,
Speed of electron = Ve
Speed of proton vp= 2ve
Magnitude of the force F = qvBsin∅
Force acting on electron Fe = qe.ve.Bsin∅
Force acting on proton Fp = qp.vp.Bsin∅
Fp = -2 qe.ve.Bsin∅
Fp = -2Fe
Negative sign shows the direction of Force on proton is opposite to the direction of force on electron.
Answer:
Temperature after ignition=7883.205 K
Explanation:
The number of moles is,
n=PV/RT
=(1.18x10^6)(47.9x10^-6)/8.314(325)
= 0.0209 moles
a) In this process volume is constant
Q=U
=nCv.dT
dT= Q/nCv
=1970/(1.5x8.314)(0.0209)
= 7558.205 K
The final temperature is,
= 7558.205+325
= 7883.205 K
Answer:
0.13
Explanation:
Draw a free body diagram. There are three forces:
Weight force mg pulling down.
Normal force N pushing perpendicular to the incline.
Friction force Nμ pushing parallel up the incline.
Sum of the forces perpendicular to the incline:
∑F = ma
N − mg cos θ = 0
N = mg cos θ
Sum of the forces parallel down the incline:
∑F = ma
mg sin θ − Nμ = ma
mg sin θ − mgμ cos θ = ma
g sin θ − gμ cos θ = a
gμ cos θ = g sin θ − a
μ = (g sin θ − a) / (g cos θ)
Given a = 3.3 m/s² and θ = 27°:
μ = (9.8 m/s² sin 27° − 3.3 m/s²) / (9.8 m/s² cos 27°)
μ = 0.13
Okay whats the question though?
