Answer:
29.2 ft/s
Explanation:
The distance of the light's projection on the wall
y = 13 tan θ
where θ is the light's angle from perpendicular to the wall.
The light completes one rotation every 3 seconds, that is, 2π in 3 seconds,
Angular speed = w = (2π/3)
w = (θ/t)
θ = wt = (2πt/3)
(dθ/dt) = (2π/3)
y = 13 tan θ
(dy/dt) = 13 sec² θ (dθ/dt)
(dy/dt) = 13 sec² θ (2π/3)
(dy/dt) = (26π/3) sec² θ
when θ = 15°
(dy/dt) = (26π/3) sec² (15°)
(dy/dt) = 29.2 ft/s
Answer:
The energy stored is: 62.5 Joules
Explanation:
Given
--- spring constant
--- stretch
Required
The amount of energy
This is calculated as:




1. Air resistance (therefore, the air density, shape (aerodynamic or not), and surface area affected
2. The gravitational acceleration constant (g = 9.8 m/s^2 on Earth)
Answer:
The poles of an electromagnet can even be reversed by reversing the flow of electricity. If a wire carrying an electric current is formed into a series of loops, the magnetic field can be concentrated within the loops. ... All of their little magnetic fields add together, creating a stronger magnetic field.
Explanation:
Answer:
d = 1.13*10^{-4}m = 0.113mm
Explanation:
To find the minimum diameter, that allow to antiproton circulate in the chamber without touching the walls, you use the following formula for the radius of the trajectory of a charged particle in a constant magnetic field.
(1)
r: radius of the trajectory
m: mass of the antiproton = 9.1*10-31 kg
v: velocity of the antiproton = 4.0*10^4 m/s
B: magnitude of the magnetic field = 4.0mT = 4.0*10^-3 T
q: charge of the antiproton = +1.6*10^{-19}C
You replace the values of the parameters in (1):

Then, the diameter of the chamber must be, at least:
d=2r = 2(5.68*10^-5) = 1.13*10^{-4}m = 0.113mm