Answer: C and D
Explanation: Analog Signals are generally much prone to even subtle noises. Also, they lose sound quality through multiple 'generations.' (B is true, but partially.)
1) The electric potential at a distance r from a single point charge is given by
![V(r) = k \frac{q}{r}](https://tex.z-dn.net/?f=V%28r%29%20%3D%20k%20%20%5Cfrac%7Bq%7D%7Br%7D%20)
where k is the Coulomb's constant, q is the charge and r is the distance from the charge.
The charge in this problem is
![q=2.2 \mu C =2.2 \cdot 10^{-6} C](https://tex.z-dn.net/?f=q%3D2.2%20%5Cmu%20C%20%3D2.2%20%5Ccdot%2010%5E%7B-6%7D%20C)
So the potential at distance
![r=6.3 m](https://tex.z-dn.net/?f=r%3D6.3%20m)
is
![V=k \frac{q}{r}=(8.99 \cdot 10^9 Nm^2 C^{-2}) \frac{2.2 \cdot 10^{-6} C}{6.3 m}=3139 V](https://tex.z-dn.net/?f=V%3Dk%20%5Cfrac%7Bq%7D%7Br%7D%3D%288.99%20%5Ccdot%2010%5E9%20Nm%5E2%20C%5E%7B-2%7D%29%20%20%5Cfrac%7B2.2%20%5Ccdot%2010%5E%7B-6%7D%20C%7D%7B6.3%20m%7D%3D3139%20V%20%20)
2) By using the same formula as before, we can find the electric potential at distance r=99 m from the charge:
The term that describes the movement of an object under the influence of gravity without air resistance is free fall
Answer:
B.)Angular momentum is always conserved
Explanation:
Angular momentum is given by:
![L=mvr](https://tex.z-dn.net/?f=L%3Dmvr)
where
m is the mass of the object
v is its speed
r is the distance between the object and the centre of its circular trajectory
In absence of external torques, angular momentum is always conserved. That means that for the spinning star, if its radius r decreases (because it shrinks), in order for L (the angular momentum) to be conserved, the speed (v) must increases, therefore the spinning star speeds up.
So, the correct choice is
B.)Angular momentum is always conserved
Is this the full question